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Verdich [7]
3 years ago
12

a store is having a sale on almonds and jellybeans for 2 pounds of almonds and 3 pounds of jellybeans the total cost is $15 for

6 pounds of almonds and 5 pounds of jellybeans total total cost is $35 find the cost of each pound of almonds and each pound of jellybeans
Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

$5.50 + $10.50 = $16

Step-by-step explanation:

6a + 5b = $34

2a + 3b = $16

...Solving by elimination

6a + 5b = 34

-3(2a + 3b = 16)

-4b = -14

b = 14/4 0r $3.50, cost of each pound of jelly beans.

a,cost of each pound of almonds = $2.75  %2816-+3%283.50%29%29%2F2+=+2.75

...checking Using:

2a + 3b = $16

$5.50 + $10.50 = $16

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Step-by-step explanation:

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7 0
3 years ago
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Sonbull [250]

Answer:

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3 years ago
Hey can anyone pls answer these math problems!!
Zepler [3.9K]

Answer:

1={5 and 3} 2={0} 3={0.209 and 4.791} 4={-3 and 4} 5={1 and 9} 6={-4.303 and -0.697}

Step-by-step explanation:

Your probably confused on what a, b, and c means.

The problems are written like this.

ax^2+bx+c=0

That formula finds the zeros.

For example 1:

x^2-8x+15=0\\ax^2-bx-c\\a=1\\b=-8\\c=15

Then use the formula

x=\frac{-b+-\sqrt{b^2-4ac} }{2a} \\\\x=\frac{-(-8)+-\sqrt{-8^2-4(1)(15)} }{2} \\x=\frac{8+-\sqrt{64-60} }{2} \\\\x=\frac{8+-2}{2}\\

If plus then 5, if minus then 3

CHECK:

x^2-8x+15=0\\5^2-8(5)+15=0\\25-40+15=0\\0=0\\3^2-8(3)+15=0\\9-24+15=0\\0=0

Hope this helps you understand how to do this by yourself.  Now to do the rest ;-;

5 0
2 years ago
Show that X^2-8x+20 can be written in the form (x-a)^2+a
svlad2 [7]

Answer:x^2 + 8x + 20

a = 1

b = 8

c = 20

Discriminant = b^2 - 4ac

=> 8^2 - 4(1)(20)

=> 64 - 80

=> -16

As -16<0

So, equation has no real roots

I hope this will help you

(-:

Step-by-step explanation:

8 0
3 years ago
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