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Verdich [7]
3 years ago
12

a store is having a sale on almonds and jellybeans for 2 pounds of almonds and 3 pounds of jellybeans the total cost is $15 for

6 pounds of almonds and 5 pounds of jellybeans total total cost is $35 find the cost of each pound of almonds and each pound of jellybeans
Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

$5.50 + $10.50 = $16

Step-by-step explanation:

6a + 5b = $34

2a + 3b = $16

...Solving by elimination

6a + 5b = 34

-3(2a + 3b = 16)

-4b = -14

b = 14/4 0r $3.50, cost of each pound of jelly beans.

a,cost of each pound of almonds = $2.75  %2816-+3%283.50%29%29%2F2+=+2.75

...checking Using:

2a + 3b = $16

$5.50 + $10.50 = $16

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$10,000+8.55 sales tax
Pavlova-9 [17]

Answer:

$10,008.55

Add 10000, and 8.55 to give the total.

10,000.00

The cents will be .55 since the $10,000 does not have any cents included.

The $8 will stay since the $10,000 does not have any dollars below 10 dollars.

So, the answer will be $10,008.55

4 0
3 years ago
HELP ME WITH THIS QUESTION PLEASE
lara [203]

Answer:

  • 0.79

Step-by-step explanation:

all you really need to do is multiply your decimal (15.8) by your percent (5) so, you problem would look like 15.8(.05) (note it is .<em>0</em>5 because there need to be 2 decimal places) so, your answer is .79

6 0
3 years ago
Enter the coordinates of the vertices of r(180,0) and t(3,-2) (QRST) will give crown
Viktor [21]

Answer:

Step-by-step explanation:

From the graph attached,

Coordinates of the vertices are,

Q(1, 3), R(3, -3), S(0, -2) and T(-2, 1)

Following the rule of translation by 3 units to the right and 2 units down T_{(3, -2)}

(x, y) → (x+3, y-2)

Q(1, 3) → Q''(4, 1)

R(3, -3) → R"(6, -5)

S(0, -2) → S"(3, -4)

T(-2, 1) → T"(1, -1)

Following rule r_{(180,\text{O})} (rotation of a point by 180° about the origin) will give the image points,

(x, y) → (-x, -y)

Q"(4, 1) → Q'(-4, -1)

R"(6, -5) → R'(-6, 5)

S"(3, -4) → S'(-3, 4)

T"(1, -1) → T'(-1, 1)

7 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
Read 2 more answers
You deposit $4300 in an account that earns 2% per year simple interest. The equation that represents this situation is: A(n) = 4
Likurg_2 [28]

Answer: $4902

Step-by-step explanation:

Amount = P (1 + rt)

= 4300 (1 + .02 * 7)

= 4300 (1 + .14)

= 4300 (1.14)

= 4902

3 0
4 years ago
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