The value of the investment in 5 years is $5805.9
<h3>What is Interest ?</h3>
Interest is the amount earned over years for the amount invested.
It is given that
Principal = $5000
Rate = 3%
Compounded Quarterly
Time = 5 years
Amount = ?
The Amount is given by the formula
Amount = P( 1 + (r/n))ⁿˣ
Here n = t = time period for which the investment has been done.
Amount = 5000( 1+(3/4 * 100)⁴ˣ⁵
Amount = 5000 (1.16)
Amount = $ 5805.9
Therefore , The value of the investment in 5 years is $5805.9
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Answer: Mean Score = 50 Range = 31
Step-by-step explanation:
58+76+40+35+46+45+0+100=400
400/8=50
Range = subtract smallest number from largest number
54 - 23 = 31
Answer: A. A=(1000-2w)*w B. 250 feet
C. 125 000 square feet
Step-by-step explanation:
The area of rectangular is A=l*w (1)
From another hand the length of the fence is 2*w+l=1000 (2)
L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.
Express l from (2):
l=1000-2w
Substitude l in (1) by 1000-2w
A=(1000-2w)*w (3) ( Part A. is done !)
Part B.
To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))
w1=0 1000-2*w2=0
w2=500
Wmax= (w1+w2)/2=(0+500)/2=250 feet
The width that maximize area A is Wmax=250 feet
Part C. Using (3) and the value of Wmax=250 we can write the following:
A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets
You would need two different lines to complete this as lines cannot be both parallel and perpendicular (these are opposites). The answers would be:
Parallel: x = 2
Perpendicular: y = -2
In order to find these, we first need to see that the original line of x = -1 is a horizontal line. Therefore, any line that is parallel should be horizontal as well. To get a horizontal line through the point (2, -2), the only option is x = 2.
Similarly, with the perpendicular line, if the original line is horizontal, the new line must be vertical. The only vertical line that goes through (2, -2) is y = -2.
30%*470=141 (So the number of students in 8 grade is 141)
