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Alisiya [41]
3 years ago
14

How many times can 14 go into 100

Mathematics
2 answers:
pogonyaev3 years ago
4 0
14 goes into 100 7.14285 repeating times.
morpeh [17]3 years ago
3 0

Answer:

\frac{50}{7} times can 14 go into 100.

Step-by-step explanation:

Say x be the times when 14 can go into 100.

'Times' in the above statement means multiplication operation.

So, the equation for the given statement becomes:

x\times 14=100

To solve the value of 'x', we shift the number '14' to other side of the equation and operation applied will be division.

Solving the above equation, we get:

x=\frac{100}{14}=\frac{50}{7}=7\frac{1}{7}

\frac{50}{7} times can 14 go into 100.

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Sandra wants to wrap a gift box 6 inches in length, 4 inches in height, and 13 inches in width. How much wrapping paper does San
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Which equation has the least steep graph? A. y = x + 6 B. y = -x - 9 C. y = 2x + 1 D. y = -7x - 2
maria [59]

Answer:

A and B.

Step-by-step explanation:

<h3>To get to know the graph with least slope, we have to write all equations in the form <u>y=mx + c. </u></h3>

where m is the slope and c is the the y-intercept.

A. y = x + 6

For this equation m = 1

B. y = -x - 9  

For equation B, m = -1

C. y = 2x + 1  

In this equation, m = 2  

D. y = -7x - 2

In equation D, m = -7

The equation with the highest slope is D while the one with the least slope/steep is <em>A and B.</em>

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Answer:

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Step-by-step explanation:

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32​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
Tems11 [23]

Answer:

a) P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

b) P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

c) P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.32)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

Part b

P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]

P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211  

P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

Part c

P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264

P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218

P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123

P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

6 0
3 years ago
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