Answer:
(5 - y) ^3 = 125 - 75y + 15y^2 - y^3
Step-by-step explanation:
Binomial expression
1
1. 1
1. 2. 1
1. 3. 3. 1 --------power of 3
( 5 - y) ^3
( 5 - y) (5 - y) (5 - y)
( a + b) ^3 = a^3 + 3a^2b + 3ab^2 + b^3
a = 5
b = -y
( 5 - y) ^2 = ( 5 - y) (5 - y)
= 5( 5 - y) - y(5 - y)
= 25 - 5y - 5y + y^2
=(25-10y+y^2)
( 25 - 10y + y^2)( 5 - y)
= 5(25 - 10y + y^2) - y( 25 - 10y + y^2)
= 125 - 50y + 5y^2 - 25y + 10y^2 - y^3
Collect the like terms
= 125 - 50y - 25y + 5y^2 + 10y^2 - y^3
= 125 - 75y + 15y^2 - y^3
Question 4- You need to subtract the shortest bolt from the longest bolt, or 1 1/4 minus 3/8. Make 1 1/4 improper and make the denominator 8 so multiply 5x2=10 and 4x2=8. 10/8 - 3/8 equals 7/8 and thats your final answer. Hope this helped ;)
Please, for clarity, use " ^ " to denote exponentiation:
Correct format: x^4*y*(4) = y*x^2*(13)
This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.
Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.
The question here is whether you can find this x^2 + 2xy + y^2 in your
"X4y(4) = yx2(13)"
Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.
The answer is <span>a. $1.75 + $0.25x ≤ $15; x ≤ 53 miles
</span>
x - the number of miles
C - the cab charge
<span>A cab charges $1.75 for the flat fee and $0.25 for each mile: C = 1.75 + 0.25x.
</span><span>Eddie has $15 to spend. So, he cannot spend more than 15 on the cab and the maximum amount he can spend is 15. Therefore:
</span>1.75 + 0.25x ≤ 15
Now, let's solve it:
0.25x ≤ 15 - 1.75
0.25x ≤ 13.25
x ≤ 13.25 / 0.25
x ≤ 53
