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polet [3.4K]
2 years ago
11

There is a bag with only red marbles and blue marbles.

Mathematics
1 answer:
Rufina [12.5K]2 years ago
7 0
Hello I hope I can help you with this!!

EXPLANATION:
first we work out what all the marbles equal which is 9/9=63

Then we work out what 1/9 of the marbles are! Which is 1/9= 7 marbles!!

Then we work out what 5/9 of them are! Which is 5/9= 35 marbles

Then now we work out 4/9 which is our RED marbles! We do 4 times 7 which equals 28 red marbles!!

if you want to check to add the two numbers and they equal 63!

ANSWER= 28 red marbles
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Find the equation of the line through the points (-2,5) and (3,-10). Give your answer in slope-intercept form.
Brilliant_brown [7]
m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-10 - 5}{3 - (-2)} = \frac{-15}{3 + 2} = \frac{-15}{5} = -3

y - y₁ = m(x - x₁)
 y - 5 = -3(x - (-2))
 y - 5 = -3(x + 2)
 y - 5 = -3(x) - 3(2)
 y - 5 = -3x - 6
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      y = -3x - 1
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3 years ago
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Sergio039 [100]
The answer is the 2nd choice, number of sales.

The function described f(x) = B + Cx
5 0
2 years ago
Parallel to y =9x 3, y-intercept at -2
Mashutka [201]
Slope-intercept form:
y=mx+b
m=slope
b=y-intercept

We have this line: y=9x+3; a line parallel to this line (y=9x+3) will have the same slope; therefore m would be equal to 9 (m=9).

Data:
m=9
b=-2
y=mx+b
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3 0
3 years ago
Point Q is located at (-4, 6). Point R is located at (8, 6) What is the distance from point Q to point R?
Stels [109]

Answer:

12 units

Step-by-step explanation:

Notice that as we go from Q to R, x (the horizontal distance) increases by 12 and y (the vertical distance) does not change.  Thus, the distance between the two points is merely the horizontal distance, 12 units.

8 0
3 years ago
Al trazar en el plano cartesiano el angulo a cuyo lado terminal es el punto de ( 3,4). Los valores de las funciones del coseno y
Igoryamba

Answer:

cos(\alpha)=\frac{3}{5}=0.6

cosec(\alpha)=\frac{5}{4}=1.25

Step-by-step explanation:

El cos(α) se define como el cociente entre el cateto adyacente y la hipotenusa.

El valor del cateto adyacente en nuestgro caso es CA = 3.

La hipotenusa se calcual de la siguiente manera:

h=\sqrt{3^2+4^2}=5

Por lo tanto, el cos(α) sera:

cos(\alpha)=\frac{3}{5}=0.6

El cosec(α)=h/CO.

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Por lo tanto, el cosec(α) sera:

cosec(\alpha)=\frac{5}{4}=1.25

Espero te haya sido de ayuda!

4 0
3 years ago
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