All categories

2 years ago

|5| |-6|=5 |-6|= =5 6 =11

Mathematics

1 answer:

RoseWind [281]2 years ago

4 0

Hello,

Here in Europe, we know a nice sign"+" which means addition !!!!!!!

|5|=5
|-6|=6

|5|+|-6|=5+6=11

You might be interested in

Median for 15,17,15,16,14,18,5

Andrei [34K]

Answer:

the median is 15

Explanation:

you can find the median by arranging the numbers from smallest to largest and finding the number in the middle.

5 14 15 <u>15</u> 16 17 18

in this case, the number in the middle is 15 so the median for this data set is 15.

i hope this helps! :D

4 0

2 years ago

Whats the awnser to this question

horsena [70]

The sum of the angles of a triangle is 180º.
We have three angles:
∠yxz=3x+5
∠xzy=180º-(8x-14)
∠xyz=4x

Therefore:
(3x+5º) + [180º-(8x-14º)]+(4x)=180º
3x-8x+4x=180º-5º-14º-180º
-x=-19º
x=19º

∠yxz=3x+5º =3(19º)+5º=62º
∠xzy=180º-(8x-14)=180º-(8(19º)-14)=42º
∠xyz=4x=4(19º)=76º

Answer: m∠yxz= 62º.

8 0

3 years ago

What is the median score achieved by a student who recorded the following scores on 10 math quizzes 68 55 70 62 71 58 81 82 63 7

Vinil7 [7]

Answer:

b. 68

Step-by-step explanation:

7 0

2 years ago

This data set represents the number of cups of coffee sold in a caf_ between 8 a.m. and 10 a.m. every day for 14 days.

Elis [28]

Put numbers in order: 4,5,6,6,7,8,9,9,10,10,12,12,14,15

Cut the list into two equal parts: 4,5,6,6,7,8,9 and 9,10,10,12,12,14,15

Find middle numbers: 4,5,6,6,7,8,9 and 9,10,10,12,12,14,15

Lower quartile: 6
Upper quartile: 12

The difference of the values of the first and third quartiles of the data set is 12 - 6 = 6

5 0

2 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

2 years ago