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Reptile [31]
3 years ago
8

Simplify and Show all of your work please!

Mathematics
1 answer:
Fudgin [204]3 years ago
7 0

Answer:

\Huge \boxed{\mathrm{9}}

Step-by-step explanation:

\Rightarrow \displaystyle \frac{18 \div 2 *  3}{5-2}

Dividing first.

\Rightarrow \displaystyle \frac{9 *  3}{5-2}

Multiplying and subtracting.

\Rightarrow \displaystyle \frac{27}{3}

Division.

\Rightarrow 9

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2+4+-56×43÷20+46-53​
Pavel [41]

Answer:

-121.4.

Step-by-step explanation:

2+4+-56×43÷20+46-53​  Multiply and divide are done first:

= 2+4 + -2408 / 20 + 46 - 53

= 2 + 4 - 120.4 + 46 - 53

= -114.4 - 7

= -121.4.

8 0
3 years ago
Read 2 more answers
What expressions equal -3x^2-27
Lady_Fox [76]
Is that x for you to multiply or is that a variable.
8 0
3 years ago
The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the
gladu [14]

Answer:

Part 1) Australia 19,751,012\ people

Part 2) China 1,319,645,764\ people

Part 3) Mexico 109,712,539\ people

Part 4) Zaire 60,534,681\ people

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

P(t)=a(1+r)^t

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

a=19,169,000\\r=0.6\%=0.6\100=0.006

substitute

P(t)=19,169,000(1+0.006)^t

P(t)=19,169,000(1.006)^t

Find the  expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

P(5)=19,169,000(1.006)^5=19,751,012\ people

Part 2) China

we have

a=1,261,832,000\\r=0.9\%=0.9\100=0.009

substitute

P(t)=1,261,832,000(1+0.009)^t

P(t)=1,261,832,000(1.009)^t

Find the  expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people

Part 3) Mexico

we have

a=100,350,000\\r=1.8\%=1.8\100=0.018

substitute

P(t)=100,350,000(1+0.018)^t

P(t)=100,350,000(1.018)^t

Find the  expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

P(5)=100,350,000(1.018)^5=109,712,539\ people

Part 4) Zaire

we have

a=51,965,000\\r=3.1\%=3.1\100=0.031

substitute

P(t)=51,965,000(1+0.031)^t

P(t)=51,965,000(1.031)^t

Find the  expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

P(5)=51,965,000(1.031)^5=60,534,681\ people

8 0
3 years ago
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
PLEASE HELP!! NO LINKS PLS..
Lesechka [4]

Answer:

I think its gonna be B

Step-by-step explanation:

5 0
2 years ago
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