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3 years ago

Real world examples of: -scalene triangle -isosceles triangle -perpendicular lines

Mathematics

1 answer:

PIT_PIT [208]3 years ago

4 0

Answer:

-Scalene

Nacho chips
Sails on sailing boats

- Isosceles

Pizza slice
Roof

-Perpendicular lines

Stairs/Steps
The corner on the inside of shelves

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Use a factor tree to write the number 220 as a product of prime numbers.

lidiya [134]

Answer:

220=2²x5 x 11

Step-by-step explanation:

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3 years ago

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A function has x-intercept 3 and y-intercept 2. Which of the functions below could be this function?

Sergeeva-Olga [200]

we are given

x-intercept is 3

so,

a=3

y-intercept is 2

b=2

now, we can intercept formula of line

$\frac{x}{a} +\frac{y}{b}=1$

now, we can plug

a=3 and b=2

$\frac{x}{3} +\frac{y}{2}=1$

now, we will get rid of denominators

so, we can multiply both sides by 6

$6*\frac{x}{3} +6*\frac{y}{2}=6*1$

$2x +3y=6$

we can also write it as

$3y-6=-2x$

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3 years ago

Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k

valkas [14]

Answer:

$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as $proj_ab = \dfrac{b.a}{||a||^2} * a$

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||² = 130

$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

<em>Hence the projection of b unto a is expressed as </em> $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$ <em></em>

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3 years ago

Kamal and Anand each Lent the same sum of money for 2 years at 5 percent at simple interest and compound interest respectively.

Ivenika [448]

Answer:

amount lent: ₹6000
interest received: Kamal, ₹600; Anand, ₹615.

Step-by-step explanation:

For principal P invested at simple interest rate r, the returned value in t years is ...

A = P(1 +rt)

If K is Kamal's returned value, the given numbers tell us ...

K = P(1 +0.05·2) = 1.1P

For principal P invested at compound interest rate r, with interest compounded annually for t years, the returned value is ...

A = P(1 +r)^t

If A is Anand's returned value, the given numbers tell us ...

A = P(1.05)² = 1.1025P

This latter amount is RS.15 more than the former one, so we have ...

1.1025P = 1.1P +15

0.0025P = 15 . . . . . . . . subtract 1.1P

P = 6000 . . . . . . . . . . . divide by 0.0025 . . . . the amount lent

Kamal received 1.1P -P = 0.1P = 600 on the investment.

Each lent ₹6000. Kamal received ₹600 in interest; Anand received ₹615 in interest.

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3 years ago

the diffrence of two numbers,a and b,is 21,the diffrence of five times a and two times b is 18 what are the values of a and b

Triss [41]

Answer:

a=-8

b=-29

Step-by-step explanation:

Let's assume

first number is a

second number is b

the difference of two numbers,a and b,is 21

so, we get

$a-b=21$

we can solve for 'a'

$a=b+21$

the difference of five times a and two times b is 18

so, we get

$5a-2b=18$

now, we can plug 'a'

$5(b+21)-2b=18$

now, we can solve for b

$5b+105-2b=18$

$3b+105=18$

$3b=-87$

$b=-29$

now, we can find 'a'

$a=-29+21$

$a=-8$

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3 years ago

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