Answer:
220=2²x5 x 11
Step-by-step explanation:
we are given
x-intercept is 3
so,
a=3
y-intercept is 2
b=2
now, we can intercept formula of line

now, we can plug
a=3 and b=2

now, we will get rid of denominators
so, we can multiply both sides by 6


we can also write it as

so, option-D..................Answer
Answer:

Step-by-step explanation:
Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as 
b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)
note that i.i = j.j = k.k =1
b.a = 5(4)+11(0)-2(7)
b.a = 20-14
b.a = 6
||a|| = √5²+11²+(-2)²
||a|| = √25+121+4
||a|| = √130
square both sides
||a||² = (√130)
||a||² = 130

<em>Hence the projection of b unto a is expressed as </em>
<em></em>
Answer:
- amount lent: ₹6000
- interest received: Kamal, ₹600; Anand, ₹615.
Step-by-step explanation:
For principal P invested at simple interest rate r, the returned value in t years is ...
A = P(1 +rt)
If K is Kamal's returned value, the given numbers tell us ...
K = P(1 +0.05·2) = 1.1P
__
For principal P invested at compound interest rate r, with interest compounded annually for t years, the returned value is ...
A = P(1 +r)^t
If A is Anand's returned value, the given numbers tell us ...
A = P(1.05)² = 1.1025P
This latter amount is RS.15 more than the former one, so we have ...
1.1025P = 1.1P +15
0.0025P = 15 . . . . . . . . subtract 1.1P
P = 6000 . . . . . . . . . . . divide by 0.0025 . . . . the amount lent
Kamal received 1.1P -P = 0.1P = 600 on the investment.
Each lent ₹6000. Kamal received ₹600 in interest; Anand received ₹615 in interest.
Answer:
a=-8
b=-29
Step-by-step explanation:
Let's assume
first number is a
second number is b
the difference of two numbers,a and b,is 21
so, we get

we can solve for 'a'

the difference of five times a and two times b is 18
so, we get

now, we can plug 'a'

now, we can solve for b




now, we can find 'a'

