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3 years ago

PLEASE HELP!!!! WILL GIVE BRAINLEST ANSWER FOR MOST DETAILED

1 answer:

4 0

For

$S= \frac{a+b+c}{2}$
the area is
$area= \sqrt{S(S-a)(s-b)(s-c)}$

find S
S=(10+11+12)/2=(33)/2=16.5
$area= \sqrt{16.5(16.5-10)(16.5-11)(16.5-12)}$
$area= \sqrt{16.5(6.5)(5.5)(4.5)}$
$area= \sqrt{2654.444}$
area=51.5212
rounded
52 square inches

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A sample of bacteria is decaying according to a half-life model. If the sample begins with 200 bacteria and after 5 minutes ther

77julia77 [94]

<h2>Hello!</h2>

The answer is:

There will remain a total of 134 bacteria after 7 minutes.

Exponential decay calculations are commonly used to find the decrease of amounts of populations, bacterias, and other situations when using proportional relationships. In order to find the problem, we must remember the equation used to calculate the exponential decay.

$Decay=S(1-r)^{t}$

Where,

S, is the starting value/amount

r, is the rate (% to real number)

t, is the time elapsed.

We are given that the numbers of bacteria decrease by 50 after 5 minutes, starting with 200, and after 5 minutes the number of bacteria is 150

Calculating the rate of decrease, we have:

$Rate=\frac{Decrease}{Starting}=\frac{200-150}{200}=\frac{50}{200}=0.25$

Therefore, the rate of decrease is 0.25 or 25% (after multiplying the number by 100)

Then, substituting the given information and the rate of decrease into the decay equation, we have:

$Decay=200(1-0.25)^{\frac{t}{5}}$

Now, to calculate how many bacteria will remain after 7 minutes, we need to substitute it into the decay equation:

$Bacteria(After7Minutes)=200(1-0.25)^{\frac{7}{5}}=133.69$

So, rounding to the nearest whole number, there will remain a total of 134 bacteria after 7 minutes.

Have a nice day!

3 0

3 years ago

For each expression, combine like terms and write an equivalent expression with fever terms.

ASHA 777 [7]

Answer:

1. 7x

2. 8x - 1

3. 6x + 12

4. 3x + 4

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Step-by-Step Explanation:

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7 0

2 years ago

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in 1991, a gallup poll reported this percent to be 79%. using the data from this poll, test the claim that the percent of driver

snow_lady [41]

We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.

Given,

The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.

In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.

To report the large-sample z statistic and its p-value,

Null hypothesis,

H₀ : p = 0.79

Alternative hypothesis,

Ha : p < 0.79

Level of significance, α = 0.01

Under H₀

Test statistic,

$Z_0= \frac{\hat p - p}{\sqrt{\frac{p(1-p)}{n} } }$

Z₀ = -7.948

The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by

P-value = P(z <-7.945)

= 0.000 (from z-table)

Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.

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5 0

1 year ago

I need to know #25. What is p? Hurry please

pav-90 [236]

I got -3.........................

-7 - 7p = 3p + 23

Move the -7p over to the right....by adding
-7 = 10p +23
Move the 23 over to the left by subtracting
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7 0

3 years ago

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Help me i will give you 50 points

jeyben [28]

1) (f + g)(2) = 7 + 3 = 10 The answer is C

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3 years ago

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