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3 years ago

PLEASE HELP!!!! WILL GIVE BRAINLEST ANSWER FOR MOST DETAILED

1 answer:

4 0

For

$S= \frac{a+b+c}{2}$
the area is
$area= \sqrt{S(S-a)(s-b)(s-c)}$

find S
S=(10+11+12)/2=(33)/2=16.5
$area= \sqrt{16.5(16.5-10)(16.5-11)(16.5-12)}$
$area= \sqrt{16.5(6.5)(5.5)(4.5)}$
$area= \sqrt{2654.444}$
area=51.5212
rounded
52 square inches

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Solve this equation: -3r -6(-7-10r)

blondinia [14]

Answer: 57r + 42

Step by step explanation:

-3r - 6(-7 - 10r)

Distribute -6 through the parenthesis

-3r + 42 + 60r

Collect the like terms

57r + 42

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3 years ago

The graph below shows the distance, y, in miles, of a bird from its nest for a certain amount of time, x, in minutes:

Montano1993 [528]

Answer:

$0.2$ miles per minute represents the speed of the bird and 3 miles represents the original distance of the bird from its nest.

Step-by-step explanation:

As there is no graph mentioned here but the information are quite sufficient to answer the question.

We have points $(0,3), (5,4),(10,5)...$

From these points we can find the slope of the line .

From point slope formula $y-y_1=m(x-x_1)$

And assigning $(x,y) (0,3)$ and $(x_1,y_1) (5,4)$

$m=\frac{y_1-y}{x_1-x} =\frac{4-3}{5-0} =\frac{1}{5}=0.2$

This slope is also the speed of the bird which is $0.2\ miles\ per\ minute.$

As by plugging the values of any coordinate point we can confirm this.

Lets put $(10,5)$ , y-axis is the distance so in $10$ minutes the the distance covered by the bird must be equal to to y-axis value which is $5$ miles.

$y=0.2(x),y=0.2(10)=5\ miles$

Now as in $t=0$ the bird has started from y-intercept value $3$ so we can say that,the original distance of the bird from its nest is $3\ miles$ .

So the correct choices are: $B$ and $D$

The birds speed is $0.2\ miles$ per minute and is $3\ miles$ away from its nest.

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3 years ago

If there are 19 questions and each question has 4 answers, what is the probability she will answer at least one question correct

gregori [183]

Answer:

0.9958

Step-by-step explanation:

P(being correct) = 1/4 = 0.25

Hence, p = 0.25

n = 19

P(x ≥ 1) = p(x = 1) + p(x = 2) +... + p(x = 19)

Using the binomial probability formula :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

However, to save computation time, we could use a calculator :

Using a calculator,

P(x ≥ 1) = 0.99577

P(x ≥ 1) = 0.9958

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3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

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Answer:

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Step-by-step explanation:

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