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2 years ago

Which point is not a solution of y < -3? A. (1,-4) B. (3,0) C.(-2,-5) D.(8,-7)

Mathematics

2 answers:

Rasek [7]2 years ago

8 0

B. (3,0)
this is because the inequality states that y must be less than -3

adelina 88 [10]2 years ago

4 0

B. This is because 0 is the y of this point. 0 is NOT less than -3. Also, if you graph y <-3 the point (3,0) is not in the shaded area.

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Which fraction has the same value as 0.6

Zinaida [17]

Using the place value chart we can see that the decimal 0.6 is six tenths, so we can write 0.6 as the fraction $\frac{6}{10}$ . Notice however that $\frac{6}{10}$ is not in lowest terms so we need to divide the numerator and the denominator by the greatest common factor of 6 and 10 which is 2.

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2 years ago

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On a number line what is the distance between-3/7 and -2/3

Nikitich [7]

Is simply their difference,

$\bf -\cfrac{3}{7}-\left( -\cfrac{2}{3} \right)\implies -\cfrac{3}{7}+\cfrac{2}{3}\impliedby \textit{LCD of 21}\implies \cfrac{-3(3)+2(7)}{21}
\\\\\\
\cfrac{-9+14}{21}\implies \cfrac{5}{21}$

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3 years ago

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n

Ivanshal [37]

Answer:

a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$

Where $_nC_x$ is the number of different combinations of x success in n trials.

$_nC_x=\frac{x!}{n!(n-x)!}$

Hence,

$P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}$

$_9C_4=\frac{4!}{9!(9-4)!}=126$

$P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125$

b) Probability that at most 3 flights are on time

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

$P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)$

$P(X=0)=(0.5)^9=0.00195313$ . . . (the probability that all are not on time)

$P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625$

$P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125$

$P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625$

$P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\ P(X\leq 3) \approx 0.0293$

c) Probability that at least 8 flights are on time 

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

$P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586$

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3 years ago

A. Independent B. Inconsistent C. Equivalent D. Consistent

tangare [24]

Answer:

B. Inconsistent (No solutions exist)

Step-by-step explanation:

The linear system that consists of parallel lines are inconsistent, which means that no solutions exist.

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2 years ago

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5.15 divided by 0.24= I need an explanation

abruzzese [7]

Answer:

Step-by-step explanat

5.15=515/100

0.24=24/100

515/24=21.45

4 0

3 years ago