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bija089 [108]
3 years ago
10

Quadrilateral A' B'C'D' is the image of quadrilateral ABCD under a dilation with a scale factor of 3

Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

3

Step-by-step explanation:

A'B'C'D' is 3 times bigger than ABCD, so to get back to the original we gotta count the length of B'C' and devide by 3

9 \div 3 = 3

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Arrange the parabolas with respect tonthe postion of their vertices from left to right
agasfer [191]

Answer:

The correct answer for this question is this one:


If the x position of the vertex for f(x) is k then : 


1. f(k) => 4x+3=k, x = (k-3)/4 = (k/4)-(3/4) 

2. x = k+3 

3. x = (k+1)/2 = (k/2)-(1/2) 

4. x = 2(k+2) = 2k+4 

5. x = k+7 

6. x = k-3 

7. x = k-2 


So the order depends on the original position of the vertex k, e.g for k=0 the positions would be: 


1. -3/4 

2. 3 

3. -1/2 

4. 4 

5. 7 

6. -3 

7. -2 


So, therefore, the order would be 6 7 1 3 2 4 5



6 0
3 years ago
HELP ME PLEASE (50 points) picture below HELP PLEASE
antiseptic1488 [7]

Answer:

72.32

Step-by-step explanation:

i have spoken

3 0
3 years ago
Read 2 more answers
How do you do this???
wariber [46]

Answer:

idk im doing to same thing in class im confused too

Step-by-step explanation:

4 0
3 years ago
The equations of three lines are given below.
Yuliya22 [10]

Step-by-step explanation:

line 1 and 2 : parallel

as line 2 is actually

6x + 2y = 8

2y = -6x + 8

y = -3x + 4

so, they have the same slope (factor of x).

line 1 and 3 : neither

the slopes -3 and 3 are not parallel not perpendicular (90°).

line 2 and 3 : neither

as line 2 is parallel to line 1, it has the same relationship to line 3 as line 1.

6 0
2 years ago
Compound interest of $1000 is invested at 10% compounded continuously, the future value s at any time t in years is given by s=1
crimeas [40]

Answer: 6.93 years

Step-by-step explanation:

Given

Rate of interest is r=10\%

Future value is given by s=1000e^{0.1t}

For the investment to double itself, i.e. s=2000

\Rightarrow 2000=1000e^{0.1t}\\\Rightarrow 2=e^{0.1t}\\\\\text{Taking log both sides}\\\\\Rightarrow \ln 2=0.1t\\\\\Rightarrow t=\dfrac{\ln 2}{0.1}\\\\\Rightarrow t=6.93\ \text{years}

It takes around 6.93 years to double the investment.

8 0
2 years ago
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