Answer:
Catalan Atlas inscription
inscription
Explanation:
Answer:
2.84*10^-3 years = 0.00284*10^-3 years
Explanation:
To find the orbital period you use the following formula:
![T=\sqrt{\frac{4\pi^2r^3}{GM}}](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%5E2r%5E3%7D%7BGM%7D%7D)
r: 2.0A = 2.0(1.5*10^11m)=3*10^11 m
G: Cavendish constant = 6.67*10^-11 Nm^2/kg^2
M: mass of the sun = 1.98*10^30 kg
![T=\sqrt{\frac{4\pi^2(3*10^{11}m)^3}{(6.67*10^{-11}Nm^2/kg^2)(1.98*10^{30}kg)}}\\\\T=89839.27\ s](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%5E2%283%2A10%5E%7B11%7Dm%29%5E3%7D%7B%286.67%2A10%5E%7B-11%7DNm%5E2%2Fkg%5E2%29%281.98%2A10%5E%7B30%7Dkg%29%7D%7D%5C%5C%5C%5CT%3D89839.27%5C%20s)
Next, you calculate the time in seconds of one Earth's year:
![1\ year=365days*\frac{24\ h}{1\ day}*\frac{3600\ s}{1\ h}=31536000\ s](https://tex.z-dn.net/?f=1%5C%20year%3D365days%2A%5Cfrac%7B24%5C%20h%7D%7B1%5C%20day%7D%2A%5Cfrac%7B3600%5C%20s%7D%7B1%5C%20h%7D%3D31536000%5C%20s)
thus, you use this value to find the orbital period of the asteroid in Earth's year:
![T=89839.27\ s*\frac{1\ year}{31536000\ s}=2.84*10^{-3}\ years](https://tex.z-dn.net/?f=T%3D89839.27%5C%20s%2A%5Cfrac%7B1%5C%20year%7D%7B31536000%5C%20s%7D%3D2.84%2A10%5E%7B-3%7D%5C%20years)
Yes that is indeed racist on many levels and the fact that are government system protect or care to protect us is a bad personal and political move.
<span>Short-term memory is the part of memory that is typically used to simply store information for a short period of time, milliseconds on average. Working memory, in comparison, allows for us to take these short-term memories, recall them, and manipulate them in ways that short-term memory is incapable of handling.</span>