Answer: Z is less than Zc ∴ 1.342 < 1.96
Therefore, Null hypothesis is not Rejected.
There is no sufficient evidence to claim that students turning in their test first score is significantly different from the mean.
Step-by-step explanation:
Given that;
U = 75
X = 78
standard deviation α = 10
sample size n = 20
population is normally distributed
PROBLEM is to test
H₀ : U = 75
H₁ : U ≠ 75
TEST STATISTIC
since we know the standard deviation
Z = (X - U) / ( α /√n)
Z = ( 78 - 75 ) / ( 10 / √20)
Z = 1.3416 ≈ 1.342
Now suppose we need to test at ∝ = 0.05 level of significance,
Then Rejection region for the two tailed test is Zc = 1.96
∴ Reject H₀ if Z > Zc
and we know that Z is less than Zc ∴ 1.342 < 1.96
Therefore, Null hypothesis is not Rejected.
There is no sufficient evidence to claim that students turning in their test first score is significantly different from the mean.
5=4x+2x-7
5+7=6x
12=6x
12/6=6x/6
2=x
Answer:
False
Step-by-step explanation:
5 3/8 > 5 4/10
Both the equation show a graph of a parabola. The equation y=-x^2+1 is a parabola opening downward since the x variable has a negative sign. While the equation y=x^2 is also a parabola opening upward since x^2 is positive. Both parabola have axis of symmetry on the y-axis. Vertex for the first parabola is on (0,1) while the second parabola is at the origin.
