It shouldn't be too hard, I've been taking my practice test all day today and yesterday night and I believe i'm going to do good today on my test, just study hard and take the practice test
Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
Idk sorry I’m stuck in an iready lessssssooooooonnnn. Ahahahahah
Answer:
Enter date and time information at "From:"
Select a month and a day. Enter a year.
The year entered must be a positive number. Not zero (0).
Enter hours and minutes. Select am or pm.
The hours entered must be a positive number between 1 and 12 or zero (0).
The minutes entered must be a positive number between 1 and 59 or zero (0).
Add or Subtract Line
Enter number of days, hours and minutes
Select "add" or "subtract"
If you type "ghblxz", in the year box the computer will print "0"
If you type "1.9e2", the computer will use "190" to calculate the answer.
If you select "February 31", the computer will print "Not a Day"
Click "Click to Calculate" button. The calculated date and time will appear.
NaN = not a number
To clear the entry boxes click "Reset
