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tekilochka [14]
3 years ago
7

Write a negation of the inequality. do not use slash symbol. x>94

Mathematics
1 answer:
Serggg [28]3 years ago
8 0
X is less than 94 because a negation is a contradiction and you just stated that x is greater than 94
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ory has designed a special table with a circular cutout in the center to be filled with glass. The radius of the cutout is 7 inc
irakobra [83]

Based on the area of the tabletop with the inner circle, the area after the inner circle has been cut out is 12,309 inch².

<h3>How do we find the new area of the tabletop?</h3>

We are told that the area of the tabletop is 12,463 inch².

We then need to find the area of the circlular cutout as:

= π x radius x radius

= 3.14 x 7 x 7

= 154 inch²

The new area after the cutout is removed is therefore:

= Current area - area of circular cutout

= 12,463 - 154

= 12,309 inch ²

Rest of the question:

Area of table including the cutout is 12,463 square inches.

Find out more on area at brainly.com/question/13183446.

#SPJ1

3 0
2 years ago
Check all of the steps that would be used to solve this equation: 2(x-5)=24
aliya0001 [1]
X=17

Distribute 2(x-5)
You are left with 2x-10=24
You then want to get 2x by itself so add 10 on both sides so that you get 2x=34
Isolate x completely by dividing by 2 on both sides which then leaves you with x=17
8 0
3 years ago
Three hundred trillion, two hundred seventy-two million, seven hundred fifteen
kifflom [539]
300,000,272,000,715 tree hunnit trilliawn
4 0
4 years ago
Which is equivalent to (4xy – 3z)2, and what type of special product is it?
bazaltina [42]
Hello,

Answer D
16x²y²-24xyz+9z² a perfect square trinomial  which
le square of the difference of 3z from 4xy.
6 0
3 years ago
Read 2 more answers
Find the value of tan(sin^-1(1/2))
suter [353]

If you know that \sin\dfrac\pi3=\dfrac12, then you know right away

\tan\left(\sin^{-1}\dfrac12\right)=\tan\dfrac\pi3=\dfrac1{\sqrt}3=\dfrac{\sqrt3}3

###

Otherwise, you can derive the same result. Let \theta=\sin^{-1}\dfrac12, so that \sin\theta=\dfrac12. \sin^{-1} is bounded, so we know -\dfrac\pi2\le\theta\le\dfrac\pi2. For these values of \theta, we always have \cos\theta\ge0.

So, recalling the Pythagorean theorem, we find

\cos^2\theta+\sin^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\sqrt{1-\left(\dfrac12\right)^2}=\dfrac{\sqrt3}2

Then

\tan\theta=\tan\left(\sin^{-1}\dfrac12\right)=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}=\dfrac{\sqrt3}3

as expected.

5 0
3 years ago
Read 2 more answers
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