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tresset_1 [31]
4 years ago
9

Solve for x.

Mathematics
1 answer:
riadik2000 [5.3K]4 years ago
3 0
I got a different answer..
and i don't see it as one of your choices, also your question is confusing since you're repeating it .-.
But anyways i got \frac{6}{11} ~or~ \frac{36}{66}
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How to simplify -1.71.
Neporo4naja [7]
171/100 (simplified)
3 0
3 years ago
Solve the following word problem using any method. Show your work.
VLD [36.1K]
Let's set up two equations:
x+y=20             We know she brought total of 20, some of each so x=small y=big
20x+ 30y=450
 
 x+y= 20
   -y    -y
 ------------
 x= 20 -y

substitute into the other equation:    
20 (20-y) + 30y = 450
400 - 20y + 30y = 450
400+ 10 y = 450
10 y = 50
y= 5

So she brought  5 big cases.  Then substitute the value of y into one of the equations.

5+ x = 20 
x= 15

So we bought 15 small cases and 5 big cases. 

Hope this helps! Please give me the brainliest answer if you like it! If you have further questions, please leave a comment or add me as a friend!


5 0
3 years ago
Read 2 more answers
Using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $82,175?
stich3 [128]

Answer: 28/36 Rule calculator tells you whether your debt is too high for your income.

Step-by-step explanation:

4 0
2 years ago
Find the indefinite integral by using the substitution x = 4 sec(θ). (Use C for the constant of integration.) x2 − 16 x d
guapka [62]

Answer:

\frac{x^2-16}{2} + 16ln\frac{4}{x}  +16C

Step-by-step explanation:

Given the indefinite integral \int\limits{\frac{x^2-16}{x} } \, dx, using the substitute

x = 4 sec(θ)...1

The integral can be calculated as thus;

First let us diffrentiate the substitute function with respect to θ

dx/dθ = 4secθtanθ

dx =  4secθtanθdθ... 2

Substituting equation 1 and 2 into the integral function we will have;

\int\limits{\frac{(4sec \theta)^2-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{16sec^2 \theta-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{(16(sec^2 \theta-1)}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\from \ trig \ identity,\  sec^2 \theta - 1 = tan^\theta\\\\\int\limits{\frac{16 tan^2 \theta}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\\int\limits 16 tan^3 \theta d \theta\\\\

Find the remaining solution in the attachment.

3 0
3 years ago
In 1988, a certain model of car cost $17000. What would be the cost of that car in 2017 dollars?
baherus [9]

Answer:

$66,092.50

Step-by-step explanation:

In 1988, the car cost $17,000

Annual inflation over this period was 3.54% from 1988 to 2017

After adjusted for inflation, $17,000.00 in 1978 is equal to $66,092.50 in 2017

Therefore, the cost of that car in 2017 is closest to $66,092.50

5 0
3 years ago
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