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3 years ago

Solve for x.

1 answer:

riadik2000 [5.3K]3 years ago

3 0

I got a different answer..
and i don't see it as one of your choices, also your question is confusing since you're repeating it .-.
But anyways i got $\frac{6}{11} ~or~ \frac{36}{66}$

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A quantity with an initial value of 600 decays exponentially at a rate of

Snowcat [4.5K]

Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

$Q(t) = 600(1 - 0.0005)^{t}$

What is the value of the quantity after 87 months, to the nearest hundredth?

6 years = 6*12 = 72 months

So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).

$Q(t) = 600(1 - 0.0005)^{t}$

$Q(1.2083) = 600(1 - 0.0005)^{1.2083} = 599.64$

The value of the quantity after 87 months will be of 599.64.

8 0

3 years ago

pls help me I will give u 100 points and mark u brainliest if u can answer this 1,2,3 questions plz help

USPshnik [31]

Answer:

Question 1: 2nd option

Question 2: 3rd option

Question 3: 4th option

8 0

3 years ago

Read 2 more answers

Juan graphed the solution to the inequality on the number line.

den301095 [7]

1.first false because it gives 8>8, that is false , but it is written 8=8
2.false because it gives 12>8 but written -12<8
3.gives 10>8, and it is written the same true
4.gives 4>8, but written 4<8

3 0

3 years ago

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Subtract 10 from k, then divide 4 by the result Do not simplify any part of the expression.

Alex787 [66]

Answer:

4k-40

Step-by-step explanation:

you first bracket the expression k-10 you then multiply it by 4

7 0

3 years ago

Can you help please

Snezhnost [94]

Answer:

Step-by-step explanation:

thatt all

4 0

3 years ago