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BigorU [14]
3 years ago
10

Someone who knows the remainder theorem help!​

Mathematics
1 answer:
Damm [24]3 years ago
5 0

Answer:

○ D. Yes, x = 12 is a zero of the polynomial.

The quotient is x + 22, and the remainder is 0.

Step-by-step explanation:

On a second thought, I knew something similar to that theorem because factoring them would determine if it has a remainder:

[x - 12][x + 22]

I am joyous to assist you anytime.

* I apologize for the previous answer I gave you.

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Add the two expressions.<br> 69 + 1 and q + 11<br> Enter your answer in the box.<br> Please help!!
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A study to compare the mean level of LDL cholesterol in male and female students who do not exercise regularly gave the data sho
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Female:                                     Male:
60                                              35
96                                             109
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n₁=no. of entries=3                    n₂=no. of entries=3
s₁=sample standard                   s₂=sample standard 
      deviation=35.005                       deviation=43.924
x₁=sample mean=60.666           x₂=sample mean=58.333

Here s and x are calculated from calculator.
Now,
for significance level
1-α=90%
1-α=0.9
α=0.1
α/2=0.05

As population variances are unknown for both Male and female so the best suitable formula is

    (x₁ - x₂) ± tα/2,v₁ * \sqrt{ \frac{s_1^2 }{n_1} + \frac{s_2^2}{n_2} }
   ........1

where v(degree of fredom)=(s₁²/n₁+s₂²/n₂)² / ((s₁²/n₁)²/n₁-1)+(s₂²/n₂)²/n₂-1))
    by putting values 
           v=3.81026
From Statistics table,
      See the t table at α/2=0.05  and v=3.81026
use interpolation as v value is not in the table,
      3.81026-3/4-3 = x-3.182/2.776-3.182
                          x= 2.853
by putting values in eq. 1 we get
  
(60.666-58.333) ± (2.853)*\sqrt{ \frac{35.005^2 }{3} + \frac{43.924^2}{3} }      

  2.333 ± 92.516 is the correct answer.


8 0
2 years ago
<img src="https://tex.z-dn.net/?f=1-%20%5Cfrac%7Bx%7D%7B2%7D%20%5C%20%20%5Ctextgreater%20%5C%20%20-4" id="TexFormula1" title="1-
Nat2105 [25]

Answer:

x

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-\frac{x}{2} > -5

x

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