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3 years ago

What are the vertices of PQR?

Mathematics

2 answers:

andrew-mc [135]3 years ago

6 0

Answer:

your answer is C

Step-by-step explanation:

vertices neither contain angle nor contain complement

valentinak56 [21]3 years ago

6 0

Answer:

C. P, Q and R.

Step-by-step explanation:

In geometry to express verticles, we use only the capital letter for that point.

It's not A because that's the symbol to represent angles.

It's not B because of the right answer in into the options.

it's not D because having both capital letters with the lines above means the line between those points.

The correct answer is C.

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The accompanying data represent the daily (for example, Monday to Tuesday) movement of Johnson & Johnson (JNJ) stock for

egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

The lower bound is of 0.484.
The upper bound is of 0.7292.

The interpretation is that we are 95% sure that the true proportion of all days in which the JMJ stock increases is between 0.484 and 0.7292.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

Supposing that it increases on 37 out of 61 days:

$n = 61, \pi = \frac{37}{61} = 0.6066$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292$

The 95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are 95% sure that the true proportion of all days in which the JMJ stock increases is between 0.484 and 0.7292.

A similar problem is given at brainly.com/question/16807970

4 0

2 years ago

On a map the perimeter of the is 0.251 meters. The actual perimeters of the park is 1,000 times as large. What is the actual per

raketka [301]

The actual perimeter of the park is $\boxed{\bf251{\text{ meters}}}$ .

Further explanation:

Given:

The perimeter of the park is on a map $0.251{\text{ meters}}$ . The measured perimeter of the park is 1000 times as large.

Calculation:

The distance of the closed figure is called as the perimeter.

The perimeter of the attached Figure 1 can be calculated as,

$\begin{aligned}{\text{Perimeter}}&=a+a+b+b\\&=2\left({a+b}\right)\\\end{aligned}$

Here, $x,y{\text{ and }}z$ is the length of the shape.

From place value chart, 10 tens is equal to 1 hundreds.

Tenths are one place after the decimal and hundredths are two places after the decimal.

Two tenths can be written in the form of decimal as follows:

$\dfrac{2}{{10}}=0.2$

Five hundredths can be written in the form of decimal as follows:

$\dfrac{5}{{100}}=0.05$

One thousandths can be written in the form of decimal as follows:

$\dfrac{1}{{1000}}=0.001$

Therefore, the number 0.251 can be written as,

$\begin{aligned}0.251&=\frac{2}{{10}}+\frac{5}{{100}}+\frac{1}{{1000}}\\&=0.2+0.05+0.001\\&=0.251\\\end{aligned}$

On the map the perimeter of the park is $0.251{\text{ meters}}$ .

Let ${\text{P}}$ be the actual perimeter of the park.

The actual perimeter of the park can be calculated as follows,

$\begin{aligned}{\text{P}}&=0.251\times1000\\&=251{\text{ meters}}\\\end{aligned}$

Thus, the actual perimeter of the park is $\boxed{\bf251{\text{ meters}}}$ .

Learn more:

1. Learn more about problem on function brainly.com/question/1632445

2. Learn more about problem on triangle brainly.com/question/7437053

3. Learn more about problem on range and domain of functions brainly.com/question/3412497

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Numbers

Keywords: Perimeter, park, map, , measured, 1000 times large, distance, closed figure, length, shape, place value chart, hundreds, tenths.

6 0

3 years ago

Read 2 more answers

Tabular representations for the functions f, g, and h are given below. Write g(x) and h(x) as transformations of f(x).

Leto [7]

Answer:

the answer for g is -3 that is all I know

4 0

2 years ago

Read 2 more answers

Find out the Range coefficient of the range

Alex777 [14]

Answer:

0.4494

Step-by-step explanation:

Given :

marks number of students

20-29 8

30-39 12

40-49 20

50-59 7

60-69 3

The range Coefficient is obtained thus :

Range Coefficient = (Xm - Xl) / (Xm + Xl)

Where ;

Xm = Mid value of highest class = (60+69)/2 = 64.5

Xl = Mid value of lowest class = (20+29)/2 = 24.5

Range Coefficient = (64.5 - 24.5) / (64.5 + 24.5)

Range Coefficient = 40 / 89 = 0.4494

7 0

2 years ago

PLEASE HELPPPPP!!!! DUE VERY SOON!!!!

REY [17]

Answer:

-1

-4

Step-by-step explanation:

7 0

3 years ago