Answer:
The group's claim is not supported at 1% significance level.
Step-by-step explanation:
given that a local group claims that the police issue more than 60 speeding tickets a day in thire area
The data they collected for 2 weeks is given below:
70 48 41 68 69 55 70
57 60 83 32 60 72 58
![\bar x = 60.2\\s = 12.9\\n=14](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2060.2%5C%5Cs%20%3D%2012.9%5C%5Cn%3D14)
Std error of mean = ![\frac{12.9}{\sqrt{14} } \\=3.4477](https://tex.z-dn.net/?f=%5Cfrac%7B12.9%7D%7B%5Csqrt%7B14%7D%20%7D%20%5C%5C%3D3.4477)
![H_0: \bar x=60\\H_a: \bar x >60](https://tex.z-dn.net/?f=H_0%3A%20%5Cbar%20x%3D60%5C%5CH_a%3A%20%5Cbar%20x%20%3E60)
(Right tailed test at 1% significance level)
Mean difference = 0.10
Test statistic t with df 13 = mean difference/std error
= 0.029
p value = 0.4886
Since p >0.01, we accept null hypothesis
The group's claim is not supported at 1% significance level.
1.
25%
.3 + .2 + .15 + .1 = .75
1.00 - .75 = .25
2.
120 students
There are 400 total students
.3 * 400 = 120
4.
tennis-
.1 * 400 = 40 students prefer tennis
football-
.25 * 400 = 100 students prefer football
140 students like football/tennis
5.
400 students
There are four quarters in a whole
.25% = 100
100 * 4 = 400
Answer:
-10
Step-by-step explanation:
-2.5 times 4
-10
Let x = your number.
(x - 17) * -7 = -35. Divide each side by -7.
(x - 17) = 5. Add 17 to each side.
x = 22.
Your number is 22
<span>Chris' average speed is 3.5mph:
Lets take Chris' brother speed = B
then Chris speed = (B+ 1) mph-------given in the question
and:
The average speed for covering 18 miles= chris' average speed + his brother's
average speed = (B+ 1) + B
since Speed = Distance covered / time taken
then average speed for 18 miles can also be found by: 18 miles/3 hours = 6 miles per hour
then we have; (B+ 1) + B = 6mph
(B +1) = (6-B)
B+B = 6-1=5
2B=5
B=5/2=2.5 mph (this is Chris' brother average speed)
Hence Chris' average speed is = B+1= 2.5+1= 3.5mph</span>