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german
3 years ago
5

Adding and subtracting polynomials(6x² - 3x - 1) - (x + 8)​

Mathematics
1 answer:
Lynna [10]3 years ago
6 0

Answer:

Simplify equation :  

6x^2 - 4x - 9

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A company produces and sells CDs. There is a fixed cost of $2000 and $5 per CD manufactured. The manufacturer sells each CD for
OlgaM077 [116]
Call the production cost 'C', the revenue 'R' and the number of CDs 'n': 

C=2000+5n
R=10n
By definition Profit P = R-C, therefore P=10n-2000+5n = 5n-2000. 
7 0
3 years ago
What is the answer to this question<br> Possible Answers <br> A.4.5<br> B.5.4<br> C.9.1<br> D10.9
vova2212 [387]
The answer is B. 5.4
7 0
3 years ago
Please help I don’t understand how to do these
steposvetlana [31]

Answer:

I think there would be 86 blue marbles

x=4(106 - x ) + 6

x= 424 - 4x + 6

5x= 430

x= 86 blue marbles

Tell me if I'm wrong, hope this helps.

3 0
3 years ago
A fair coin is to be tossed 20 times. Find the probability that 10 of the tosses will fall heads and 10 will fall tails, (a) usi
lbvjy [14]

Using the distributions, it is found that there is a:

a) 0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

b) 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

c) 0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item a:

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 20 tosses, hence n = 20.
  • Fair coin, hence p = 0.5.

The probability is <u>P(X = 10)</u>, thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{20,10}.(0.5)^{10}.(0.5)^{10} = 0.1762

0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item b:

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • The binomial distribution is the probability of <u>x successes on n trials, with p probability</u> of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

The probability of an exact value is 0, hence 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item c:

For the approximation, the mean and the standard deviation are:

\mu = np = 20(0.5) = 10

\sigma = \sqrt{np(1 - p)} = \sqrt{20(0.5)(0.5)} = \sqrt{5}

Using continuity correction, this probability is P(10 - 0.5 \leq X \leq 10 + 0.5) = P(9.5 \leq X \leq 10.5), which is the <u>p-value of Z when X = 10.5 subtracted by the p-value of Z when X = 9.5.</u>

X = 10.5:

Z = \frac{X - \mu}{\sigma}

Z = \frac{10.5 - 10}{\sqrt{5}}

Z = 0.22

Z = 0.22 has a p-value of 0.5871.

X = 9.5:

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 10}{\sqrt{5}}

Z = -0.22

Z = -0.22 has a p-value of 0.4129.

0.5871 - 0.4129 = 0.1742.

0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

A similar problem is given at brainly.com/question/24261244

6 0
3 years ago
Juan's company spent $ 2,350 on an event.They spent about $2,500 on food and about $900 on entertainment.What could the actual c
kodGreya [7K]
The highest amount it could be is 2,499 + 899= 3,898 which could be rounded to 3,900
7 0
3 years ago
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