Six divided by five maybe and add a 1
Answer:
We need to find the value of b to make 8b - 27 be equal to 5, so:
8b - 27 = 5
We solve the equation:
8b = 5 + 27
8b = 32
We divide both sides by 8:
b = 32/8 = 4
So now, we know that b=4, and we can verify:
8*4 - 27 = 5
32 - 27 = 5 TRUE
Answer:
J 8.5 >=2.5p
Step-by-step explanation:
To do this plug in 3.4 for each version of p. The only one that would be true would be J.
Answer:
in this method a variable is expressed in terms of another variable from one equation and it is substituted in remaining equation.
Step-by-step explanation:
solve:x+2y=9 and 3x-y=13.
x+ 2y=9…be the first equation
3x-y=13…be the second equation
from first equation
x=9-2y…be the third equation substituting value of x from third equation in second equation, we get
3(9-2y)-y=13
or, 27-6y-y=13
or, y=2
now,
substituting value of y in third equation, we get,
x=9-2×2
=9-4
=5
the required value of x and y are 5&2