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Alona [7]
3 years ago
10

alo had the third highest grade oint avwrage (GPA) of a group of five. His GPA was 79, amd ir was 12 points lower thank the high

est GPA in the group and 8 points higher than the lowest GPA in the group. The fourth highest GPA was 2 points above the lowest. The second highest was 5 points below the highest. what was the fourth highest GPAbin the group
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0
The fourth highest GPA is 6
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Pls help due in 10 mins
gregori [183]

Answer:

the answer is 5

Step-by-step explanation:

hope that helps

5 0
3 years ago
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Two more than four times a number is the same as 6 more than twice the number find the number ​
Yuki888 [10]

Answer:

The number is 2. :)

Step-by-step explanation:

4x + 2 = 2x + 6

    -2            -2

4x = 2x + 4

-2x   -2x

2x = 4

/2    /2

x = 2  

7 0
2 years ago
Which rectangle has an area of 36 square units?
Umnica [9.8K]

Answer:

B

Step-by-step explanation:

dont need to know why

OOF no one answered in 4 days?! wow

5 0
2 years ago
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Find the values of x and y that make these triangles congruent by the HL Theorem.
RideAnS [48]

According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

By using equation (1) next step is to plug in y+1 for x in equation (2). So,

2 ( y + 1) + 3 = 3y + 3

2y + 2 + 3 = 3y + 3 By using distribution property.

2y + 5 = 3y + 3

2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.

2y = 3y - 2

2y - 3y = -2 Subtract 3y from each sides.

-y = -2

So, y=2

Next step is to plug in y=2 in equation (1) to get the value of x. Hence,

x= 2+1

=3

So, x=3 and y=2 make these triangles congruent.

So, the correct choice is 3. x = 3, y = 2.

7 0
2 years ago
What is the following quotient? 5/√11-√3
kati45 [8]

ANSWER

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

EXPLANATION

The given rational function is

\frac{5}{ \sqrt{11} -  \sqrt{3}}

We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of

\sqrt{11}  -  \sqrt{3}

which is

\sqrt{11}   +  \sqrt{3}

When we rationalize we obtain:

\frac{5( \sqrt{11}  +  \sqrt{3} )}{(\sqrt{11}  - \sqrt{3} )( \sqrt{11}  +  \sqrt{3} )}

The denominator is now a difference of two squares:

(a - b)(a + b) =  {a}^{2}  -  {b}^{2}

We apply this property to get

\frac{5( \sqrt{11}  +  \sqrt{3} )}{( \sqrt{11}) ^{2}    -  ( \sqrt{3}) ^{2}  )}

\frac{5( \sqrt{11}  +  \sqrt{3} )}{11   -  3}

This simplifies to

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

Or

\frac{5 }  {8}\sqrt{11}  + \frac{5 }  {8}\sqrt{3}

8 0
3 years ago
Read 2 more answers
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