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Murrr4er [49]
2 years ago
15

Find the range of the data. 62, 58, 67, 57, 59, 70, 69,61 The range is​

Mathematics
2 answers:
steposvetlana [31]2 years ago
4 0

\huge\text{Hey there!}

\large\text{The word range simply means that you have to find the DIFFERENCE}\\\large\text{between the LARGEST number and the SMALLEST number.}\\\large\text{The word difference simply means SUBTRACT.}\\\\\large\text{The \underline{largest number}}\rightarrow\large\text{\bf 70}\\\large\text{The \underline{smallest number}}\rightarrow\large\text{\bf 57}\\\\\\\\\ \huge\text{70 - 57 = \bf 13}

\boxed{\boxed{\large\text{Therefore, your \underline{answer} is: \huge\bf {13}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

jok3333 [9.3K]2 years ago
3 0

Answer:

the range is 13

Step-by-step explanation:

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Answer:

\frac{\sqrt{2} }{2}

Step-by-step explanation:

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When one leg = x, the hypotenuse = x\sqrt{2}

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\frac{1}{\sqrt{2} }  rationalize denominator.

\frac{1}{\sqrt{2}} × \frac{\sqrt{2}}{\sqrt{2} } = \frac{\sqrt{2}}{\sqrt{2} \sqrt{2} }  =  \frac{\sqrt{2} }{\sqrt{4}} =  \frac{\sqrt{2}}{2}

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2 years ago
Y=1/2 x + 2 what is the slope?
dem82 [27]

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3 years ago
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Fittoniya [83]

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2 years ago
Assume that the following data were generated using a valid and appropriate methodology. XYZ Data Analytics, Inc. Received prope
Hitman42 [59]

Using the z-distribution, as we are working with a proportion, the 95% confidence interval for the proportion of consumers who would buy the product at it's proposed price is (0.3016, 0.3830).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

179 out of 523 members indicated they would buy the new product at the proposed price, hence:

\pi = \frac{179}{523} = 0.3423

Then the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 - 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3016

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 + 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3830

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
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Answer:

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Step-by-step explanation:

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