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Stella [2.4K]
3 years ago
12

Mr. Doss reached into a bag and pulled out a handful of counters. He pulled out 16 negative counters and 27 positive counters. W

hat was the combined value of the counters?
Mathematics
1 answer:
Maurinko [17]3 years ago
8 0

Answer: 11

Step-by-step explanation:

Given: Mr. Doss pulled out 16 negative counters and 27 positive counters.

In integers we use negative sign "-" to represent the negative quantities.

So, we can represent 16 negative counters as -16.

Now, combined value of the counters = (-16) + 27

= 27-16

= 11

Hence, the combined value of the counters is 11.

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2) Find the probability of rolling a 2 or smaller.
Mamont248 [21]

There are 6 numbers in one die.

There are 2 numbers that are less than or equal to 2, they are 1 and 2

The probability of something happening is the number of chances / total number

The probability would be 2/6, which can be reduced to 1/3

8 0
3 years ago
What time and day will it be <br> 154hr 36 mins after Thursday 1:26pm?
loris [4]

Answer:

12:02 AM on the next Thursday

Step-by-step explanation:

First we wanna find how many days that is.  154/24.  that is 6 and 5/12 days.

5/12 of a day is equal to 10/24, so 10 hours, sice there are 24 hours in a day.

so that's 10 hours and 36 minutes which equals 2:02 pm + 10 hours 12:02 AM on Friday

Now just add the 6 days so 12:02 AM on the next Thursday

5 0
3 years ago
Mr and Mrs Baker place 12-inch rulers along the length of a rug. They each line up 3 rulers along the edge of the rug. What is t
Daniel [21]
3 Feet
12 inches= 1 foot
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4 0
3 years ago
Read 2 more answers
Choose one of the squares facts from problem 1?
egoroff_w [7]
I think you forgot to put in the image
8 0
3 years ago
At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).
Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

\rm 3x (x-1) (x^5)= 0

\rm x^5 =0, \ \  x=0\\\\ x-1 = 0, \ \ x =1\\

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

7 0
2 years ago
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