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3 years ago

Factor X^2-13x+22 help pls

Mathematics

2 answers:

nikdorinn [45]3 years ago

5 0

Answer:

(x-2)(x-11)

Step-by-step explanation:

lisabon 2012 [21]3 years ago

5 0

Answer:

(x - 2)(x - 11)

Step-by-step explanation:

We have a polynomial and are asked to factor it.

Polynomial : x^2 - 13x + 22

Usually a trick I follow when factoring is that for c (in this case 22). You need to find two numbers that will multiply to it. And for b (in this case -13) you will need to find two numbers that will add to it, the same numbers you multipled for c.

x * y = 22

x + y = -13

These two numbers are -11 and -2.

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Answer:

P = 0.05

Step-by-step explanation:

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3 years ago

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Part A:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

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Thus p = 0.85

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Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

$P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\ \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\ \\ =0.9126$

Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

$\mu=npq \\ \\ =15\times0.15\times0.85 \\ \\ =1.9125$

Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The probability that the number of truthful applicants classified as liars is greater than the mean is given by:

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Step-by-step explanation:

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