Sketch a right
triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x”
and assigning angle “a” as the angle between A and H. Using Pythagorean theorem,
you will get “square root of x-squared minus 9” as the opposite side (O). Using
SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) =
x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side
over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the
algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.
Area of triangles:
0.5x9=4.5
4.5x2=9 (i divided 4 (the amount of triangles) by 2 instead of dividing 4.5 by 2)
area of square:
0.5x0.5=0.25
surface area of whole thing:
9+0.25=9.25
so the answer is 9.25
hope this helps :)
Answer:
there is no table, just a list of numbers. we need a table or maybe a ss for reference