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Rudiy27
3 years ago
5

If the scale factor between two circles is 7a/9b what is the ratio of their areas?

Mathematics
2 answers:
RideAnS [48]3 years ago
5 0
<span>. 49a2/81b2
I think the answer is B)</span>
Dvinal [7]3 years ago
5 0

Answer:  The correct option is (B) \dfrac{49a^2}{81b^2}.

Step-by-step explanation:  Given that the scale factor between two circles is \dfrac{7a}{9b}.

We are to find the ratio of the areas of the two circles.

Let r and R be the radii of the two circles and A and B be the corresponding areas.

We know that the scale factor is the ratio of the radii of the two circles.

So, we have

\dfrac{r}{R}=\dfrac{7a}{9b}\\\\\\\Rightarrow \dfrac{r^2}{R^2}=\dfrac{49a^2}{81b^2}\\\\\\\Rightarrow \dfrac{\pi r^2}{\pi R^2}=\dfrac{49a^2}{81b^2}\\\\\\\Rightarrow \dfrac{A}{B}=\dfrac{49a^2}{81b^2}.

Thus, the required ratio of the areas of the two circles is \dfrac{49a^2}{81b^2}.

Option (B) is CORRECT.

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Here, we want to calculate the percentage increase

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3 years ago
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Answer:

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4 years ago
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~ 2 x 2 x 2 = 8  (we use 2 because the radius is half of the diameter)

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3 years ago
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