Answer:
true
Explanation:
The command:
find -empty -type f -exec rm { } \;
carries out the following steps.
1) Finds all the empty files in the current directory and its subdirectories.
2) For each of the identified files, it executes the command specified as the parameter to exec option,namely, rm <filename>.
So effectively it removes all empty files in the directory tree starting at the current directory.
The device is ; a modem.
Hope this helps
Answer:
The source and destination IP addresses are 10.0.1.19 and 10.0.1.25
Explanation:
NAT or network address translation is a network protocol is used by private networks to access the internet by assigning or mapping a public IP address to the private addresses.
The host with IP address 10.0.1.19 searches for the actual destination IP address 128.119.160.183 in its private network and when it does not find it, it sends the packet to the default gateway IP address 10.0.1.25, which is where the private IP address is NATted and sent to the destination.
Answer:
The correct answer to the following question will be Error-detection.
Explanation:
Error-detection: The detection of errors caused during the transmission from the transmitter to the receiver by damage and other noises, known as Error-detection. This error-detection has the ability to resolute if something went wrong and if any error occurs in the program.
There are mainly three types of error-detection, these types can be followed:
- Automatic Repeat Request (ARQ)
- Forward Error Correction
- Hybrid Schemes
There are two methods for error-detection, such as:
- Single parity check
- Two-dimensional parity check
Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
