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3 years ago

8

Write an equation in standard form that has a slip of 6 and passes through (-1,3)

1 answer:

tamaranim1 [39]3 years ago

7 0

Answer:

<h2>6x - y = -9</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - point on a line</em>

<em />

We have

$m=6,\ (-1,\ 3)\to x_1=-1,\ y_1=3$

Substitute:

$y-3=6(x-(-1))$

$y-3=6(x+1)$

Convert to the standard form <em>Ax + By = C</em>:

$y-3=6(x+1)$ <em>use the distributive property </em><em>a(b + c) = ab + ac</em>

$y-3=6x+6$ <em>add 3 to both sides</em>

$y=6x+9$ <em>subtract 6x from both sides</em>

$-6x+y=9$ <em>change all signs</em>

$6x-y=-9$

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