Question

Write an equation in standard form that has a slip of 6 and passes through (-1,3)

Answer 1

Answer:

6x - y = -9

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

We have

$m=6,\ (-1,\ 3)\to x_1=-1,\ y_1=3$

Substitute:

$y-3=6(x-(-1))$

$y-3=6(x+1)$

Convert to the standard form Ax + By = C:

$y-3=6(x+1)$         use the distributive property a(b + c) = ab + ac

$y-3=6x+6$          add 3 to both sides

$y=6x+9$         subtract 6x from both sides

$-6x+y=9$          change all signs

$6x-y=-9$