Answer:
(5, infinitysymbol)
Step-by-step explanation:
First solve the inequality. Subtract 2 from both sides.
x + 2 > 7
x > 5
So that is one way of writing the answer and it is hopefully kind of understandable. X>5 means all the numbers greater (bigger) than 5, forever to infinity.
Interval notation is a way of writing a set or group of numbers. Interval notation uses ( ) parenthesis or [ ] square brackets. Then two numbers go inside with a comma in between. The first number is where the set of numbers start and the second number is where the set ends. You always put parenthesis around the infinity symbol or negative infinity symbol. You only use a square bracket if the inequality symbols have the "or equal to" underline under the > or <.
So x > 5 in interval notation is:
(5, infinitysymbol)
This shows that 5 is not included in the solution; and all the numbers forever bigger than five are solutions as well.
Formula d = vt
1 3/4= 1.75
1/4=0.25
So now plug into equation
To find v first to find per hr.
v = (1.75 miles) / (0.25 hrs) =
7 miles per hr
Distance per hr
d = (7 miles/hr)(1 hr) = 7 miles
In 3 hrs ?
d = (7 miles/hr)(3hr) = 21 miles
Answer:
∆ adc is congruent to ∆ abc by asa congruence rule where CA is common side,
so CD and CB are congruent therefore angle cbe is same as angle cde
so ∆ bce and ∆ dce are congruent by ASA congruence rule
Answer:
When we have a function f(x), the domain of the function is the set of all the inputs that "work" (Not only in a mathematical way, the context is also important) with the function f(x)
In this case, we have a function M(p) = $2*p
This function represents the amount of money collected depending on the number of people who ride on the ferris whell.
Then p can be only a whole number (we can not have 1.5 people, only whole numbers of people).
And we also know that the maximum capacity of the ferris is 64 people.
Then:
p ≤ 64
And we also should add the restriction:
0 ≤ p ≤ 64
(Because p can't be smaller than zero)
Such that p should also be an integer, then, the domain is:
D: p ∈ Z, p ∈ {0, 1, 2, ..., 64}
