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adoni [48]
3 years ago
8

Write an equation in standard form that has a slip of 6 and passes through (-1,3)

Mathematics
1 answer:
tamaranim1 [39]3 years ago
7 0

Answer:

<h2>6x - y = -9</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - point on a line</em>

<em />

We have

m=6,\ (-1,\ 3)\to x_1=-1,\ y_1=3

Substitute:

y-3=6(x-(-1))

y-3=6(x+1)

Convert to the standard form <em>Ax + By = C</em>:

y-3=6(x+1)         <em>use the distributive property </em><em>a(b + c) = ab + ac</em>

y-3=6x+6          <em>add 3 to both sides</em>

y=6x+9         <em>subtract 6x from both sides</em>

-6x+y=9          <em>change all signs</em>

6x-y=-9

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Answer:

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Step-by-step explanation:

y = | x | – 13

Answer:

y = |x| -13

Step-by-step explanation:

recall for any function y = f(x), to translate the function vertically by any value "a", we simply have to add "a" to f(x).

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In our case , the graph is translated vertically by 13 units (i.e a = 13) and it is to be translated downwards (i.e negative)

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Step-by-step explanation:

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