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Mathematics

1 answer:

Vesna [10]3 years ago

8 0

The answer is D because she makes 8.75 in 1 hour 17.50 in 2 hours and so on

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ABCD rhombus, AC:BD = 4:3 Perimeter ABCD = 20 cm Find: Area of ABCD

AlladinOne [14]

Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²

6 0

3 years ago

What are the zeros of f(x) = x(x − 9)?

ollegr [7]

Answer:

x = 0 , x = 9

Step-by-step explanation:

to find the zeros let f(x) = 0 , that is

x(x - 9) = 0

equate each factor to zero and solve for x

x = 0

x - 9 = 0 ⇒ x = 9

6 0

2 years ago

Read 2 more answers

In ΔEFG, the measure of ∠G=90°, EF = 38 feet, and FG = 30 feet. Find the measure of ∠F to the nearest degree.

Mamont248 [21]

Answer:

∠F = 42° to the nearest degree

Step-by-step explanation:

In this question, we are asked to calculate the value of the angle.

Kindly note that since one of the angles we are dealing with in the triangle is 90°, this means that the triangle is a right-angled triangle

Please check attachment for the diagrammatic representation of the triangle

From the diagram, we can identify that the EF is the hypotenuse and the length FG is the adjacent. Thus , the appropriate trigonometric identity to use is the cosine

mathematically;

Cosine of an angle = length of adjacent/length of hypotenuse

$Cos F = \frac{30}{38}\\Cos F = 0.7895\\F = Cos^{-1} 0.7895\\$