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3 years ago

What is the slope of a line that passes through the points 1,1 and 1,4

1 answer:

3 0

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{1})\qquad
(\stackrel{x_2}{1}~,~\stackrel{y_2}{4})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-1}{1-1}\implies \cfrac{3}{0}\impliedby und efined$

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Find lim h→0 f(2+h)-f(2)/h if f(x)=x^2+x+1

bekas [8.4K]

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Step-by-step explanation:

$\displaystyle \lim_{h \to 0} \frac{f(2+h)-f(2)}{h}$

$\displaystyle\lim_{h \to 0} \frac{(2+h)^2 + 2 + h + 1 - 2^2 - 2 - 1}{h}$

$\displaystyle\lim_{h \to 0} \frac{4 + 4h + h^2 + h - 4}{h}$

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2 years ago

Transform the given quadratic function into vertex form f(x) = quadratic function into vertex form f(x) = quadratic function int

melisa1 [442]

Answer:

Vertex form: $f(x) =(x +\frac{7}{2})^2 -\frac{53}{4}$

The vertex is $(-\frac{7}{2},-\frac{53}{4})$

Step-by-step explanation:

For a general quadratic function the form is:

$ax ^ 2 + bx + c$

For the function

$f(x) = x ^ 2+ 7x -1$

The values of the coefficients for the function are the following: $a = 1$ , $b =7$ , $c = -1$

Take the value of b and divide it by 2. Then, the result obtained squares it.

$\frac{b}{2}= \frac{7}{2}$

$(\frac{b}{2})^2=(\frac{7}{2})^2=\frac{49}{4}$

Add and subtract $\frac{49}{4}$

$f(x) = (x ^ 2 +7x +\frac{49}{4}) -\frac{49}{4}- 1$

Write the expression of the form

$f(x) = (x+\frac{b}{2})^2 +k$

$f(x) =(x +\frac{7}{2})^2 -\frac{53}{4}$

The vertex is $(-\frac{7}{2},-\frac{53}{4})$

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3 years ago