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Sedbober [7]
3 years ago
8

Find the derivative of e^(lnx)^2

Mathematics
1 answer:
trapecia [35]3 years ago
8 0
D(e^(In(x))^2)/dx = 2 In(x) * 1/x * e^(ln(x))^2 = (2e^(ln(x))^2 * In(x)) / x
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Please help me im about to fail!!!! Express your answer in scientific notation.
Illusion [34]

Answer:

3.74 x 10^5

Step-by-step explanation:

First expand the term in scientific notation into normal notation.

3.3 x 10^5   -   Here the ^5 tells us to move the decimal five places to the right, so we go from

3.30000 to

330000.00

So 3.3 x 10^5 = 330,000

Now add that to 44,000 and you get 374,000.

Return this number to scientific notation.  Move the decimal back to its spot before the 3.  We go from

374,000.00 to

3.74000

Once again the decimal has moved five places, so that is the number in the exponent of the our scientific notation, and therefore our answer is

3.74 x 10^5

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2 years ago
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Soloha48 [4]

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3 years ago
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Find the value of x so that the function has the given value. 2(x) = 2x + 7; n(x) = 17​
Galina-37 [17]

Answer:

  x = 5

Step-by-step explanation:

Maybe you have ...

  n(x) = 2x +7

and you want x for n(x) = 17.

  17 = 2x +7

  10 = 2x . . . . . . subtract 7

  5 = x . . . . . . . . divide by 2

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3 years ago
Ana had softball practice for 2 hours. She practiced pitching for 20 minutes. For what fraction of the time did she practice pit
ahrayia [7]
She spent 1/6 of the time pitching.
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3 years ago
Using the TI-84 calculator, find the area under the standard normal curve. Round the answers to four decimal places.(a) Find the
madam [21]

Answer:

a) 0.705

b) 0.976

c) 0.01

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Step-by-step explanation:

We have to find the area under the standard normal curve.

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=P(-1.98

b) area under the standard normal curve to the left of z=1.98

=P(z

c) area under the standard normal curve to the right of z= 2.34

P(z>2.34)\\=1 - P(z

d)  area under the standard normal curve that lies between z= −0.94 and z= −0.63

=P(-0.94

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3 years ago
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