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kramer
3 years ago
6

Thrice the product of two and "Y".

Mathematics
1 answer:
love history [14]3 years ago
6 0

Answer:

6Y

Step-by-step explanation:

We need to solve the statement ' Thrice the product of two and "Y" '.

Thrice means 3 times and product means multiply. It means we have to multiply 3,2 and Y.

Let the result is R. It can be calculated as follows :

R=3\times 2\times Y

We know that, 3×2 = 6

So,

R=6Y

Hence, Thrice the product of two and "Y" is 6Y.

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Step-by-step explanation:

Solve 2x^2-11x+14=0 give me 2 ways to get the 2 values of x?

The first way is to make factors by middle-term splitting. You get (x-2)(2x-7)=0, so the solution is x=2,7/2.

The other way is to use the formula for the solution of roots. Roots= (-b+ rootD)/2a, (-b-rootD)/2a, if the equation is of the form ax^2+bx+c=0. Here D is the discriminant. D=b^2-4ac

How do I solve 12x^2+11x+2=0?

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How can I prove that x^2+2x+2=0?

Is the sequence X^2 + 2x -2 =0?

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Lets assume your equation is of the form ax^2+ bx + c =0

First method :

By breaking 'b' factor of x into two parts using factors of 'ac' ( a *c)

like 2* 14 = 28 = 7* 4 ( b is 11 which could be splitted in values 7 and 4)

equation becomes 2x^2 -4x-7x+14 = 0

take out common factors 2x(x-2) -7 (x-2) = 0

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Second method:

make equation in the form of (x+h)^ 2 - k = 0 ; then x+h = +sqrt(k) and -sqrt(k)

which will give x as -h+sqrt(k) , +sqrt(k)

2x^2 - 11x +14 =0 wil become x^2 -11/2 x + 7 = 0

which is (x-11/4)^2 + 7- 121/16 =0

(x-11/4)^2 = (121/16) - 7 = 9/16

x- 11/4 = 3/4 and -3/4

x = 14/4 and 8/4 = 7/2 and 2

3 0
2 years ago
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Answer:

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Step-by-step explanation:

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Formula used:

V_{2} -V_{1} / V_{2} × 100

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V1= 186,000

7 0
3 years ago
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Step-by-step explanation:

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Answer:

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