Ask question

Ask question

All categories

3 years ago

5

Find the selling priceCost to store: $90Markup: 60%

1 answer:

lisabon 2012 [21]3 years ago

8 0

The markup is what the store adds to its cost of the item to cover expenses and give the store a profit. Find the amount of markup, and add it to the cost to find the selling price.

60% of $90 =

= 60% * 90

= 0.6 * 90

= $54

$90 + $54 = $144

The selling price is $144

You might be interested in

Emily and Tammy each opened checking accounts on the same day, intending to withdraw money for weekly expenses. Emily opened her

Lunna [17]

Answer:

15 weeks

Step-by-step explanation:

8 0

3 years ago

Grant earns $5 for each magazine he sells.Write an equation in two variables showing the relationship between the number pf maga

slega [8]

Answer:

$A=5m$

Grant will make $60 from selling 12 magazines.

Step-by-step explanation:

Let m represent number of magazine sold and A represent amount of money earned.

We have been given that Grant earns $5 for each magazine he sells. So amount earned from m magazines would be 5 times m that is $5m$ dollars.

Now, we will equate total amount earned by Grant with A as:

$A=5m$

Therefore, our required equation would be $A=5m$ .

To find the amount earned by Grant by selling 12 magazines, we will substitute $m=12$ in our equation as:

$A=5(12)$

$A=60$

Therefore, Grant will make $60 from selling 12 magazines.

3 0

3 years ago

(4x1,000)+(5x100)+(9x10)+(2x1)+(7x1/10) in standard form

Igoryamba

Answer:

4592.7

Step-by-step explanation:

Add them up:

4000 + 500 + 90 + 2 + 0.7 = 4592.7

6 0

3 years ago

Help<br> help please please

Ahat [919]

Answer:

1. A

2. C

Step-by-step explanation:

I could be wrong, that's my best guess. Im so sorry if im wrong, have a good day

7 0

3 years ago

Integration of the following function

DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

$\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}$

$d\bar{c}=\left ( -6x^{-2}+\frac{1}{6}\right )dx$

Now, integrating both sides

$\int d\bar{c}=\int \left ( -6x^{-2}+\frac{1}{6}\right )dx$

$\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1$

$\bar{c}=6x^{-1}+\frac{1}{6}x+k_1$

6 0

3 years ago