<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
Answer:
I think the way they are telling is that the triangle will move to the third quadrant,
If so, then the coordinates of P'Q'R' will just be the negative of PQR.
We need to see the table. Otherwise we can't make the observation.
x 21
----- = -----
110 100
Cross multiplication:
110 x 21 / 100
= 23.1
About 23 of the pencils are blue.
Answer:
4x+12
Step-by-step explanation:
(x+2)+(x+2)=2x+4
(x+4)+(x+4)=2x+8
(2x+4)+(2x+8)=4x+12
