#1 is 12x² -15x
#2 is fx-9x
Work out 180-96 cus it’s on a straight line then work out 180-130 then add them then and take away from 180
To make it much easier, it should be converted to the slope-intercept form
y = mx + bTo do so, 14x + 34y = 1 turns to:
34y = -14x + 1Divide both sides by 34:

Simplified:
Answer: 
Here is the graph:
Answer: y=1.5
Step-by-step explanation: Isolate the variable by dividing each side by factors that don’t contain the variable.
Answer:
y=7x+3
Step-by-step explanation:
Hi there!
We are given the equation y=7x-5 and we want to find the equation of the line that is parallel to it, and contains the point (4,31)
First, let's find the slope of y=7x-5, since parallel lines have the same slopes
The line y=7x-5 is written slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Since 7 is in the place of where m is, the slope of the line is 7
It's also the slope of the line parallel to it.
We can substitute 7 as m into the formula y=mx+b for our new line:
y=7x+b
Now we need to find b
Since the equation will pass through the point (4, 31), we can use it to solve for b; substitute 31 as y and 4 as x
31=7(4)+b
Multiply
31=28+b
Subtract 28 from both sides
3=b
Substitute 3 as b
y=7x+3
Hope this helps!