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irinina [24]
3 years ago
11

Find the cube root of 1/1,000

Mathematics
1 answer:
Anettt [7]3 years ago
8 0

we do the same as before.  Bear in mind that

1² = 1³ = 1⁴ = 1¹⁰⁰⁰⁰⁰⁰⁰⁰ = 1


\bf \cfrac{1}{1000}~~\begin{cases}1^3=1\\1000=10^3\end{cases}\implies \sqrt[3]{\cfrac{1^3}{10^3}}\implies \cfrac{\sqrt[3]{1^3}}{\sqrt[3]{10^3}}\implies \cfrac{1}{10}

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(b) The integral is equal to the area of the semicircle with radius 10. It's also under the horizontal axis, so the area is negative. The semicircle has area \frac{\pi10^2}2=50\pi, so the integral is -50π.

(c) First compute

\displaystyle\int_{30}^{35}g(x)\,\mathrm dx

which is the area of the triangle on the right. It has height and base 5, so its area is 25/2.

Then split up the desired integral as

\displaystyle\int_0^{35}g(x)\,\mathrm dx=\int_0^{10}g(x)\,\mathrm dx+\int_{10}^{30}g(x)\,\mathrm dx+\int_{30}^{35}g(x)\,\mathrm dx

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Us<br> Find the measure of 45.<br> 45 = [?]<br> 510
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5 0
2 years ago
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