I need to.find out what the blanks are please comment

Choose the Algebraic equation that matches the table

juin [17]

Answer:

C

Step-by-step explanation:

In order to write the equation, you need to identify the slope and y-intercept.

1) the y intercept is what y is when x=0. According to the table, it is -2.

2) the slope is the change in the y values over the change in the x values. Notice that the y values are increasing by one for every increase in 1 in the x values, so the slope is 1/1 or 1.

3) we can then put those values into slope-intercept form which is y=mx+b where m is the slope and b is the intercept.

4) so the equation is y=(1)x-2 or y=x-2 (they are the same)

8 0

3 years ago

When we test Upper H 0: muequals0 against Upper H Subscript a: mugreater than0, we get a P-value of 0.03. a. What would the

Anastasy [175]

Answer:

(a) The null hypothesis will be rejected.

(b) Type I error

(c) The null hypothesis will not be rejected. The error is type II error.

Step-by-step explanation:

The hypothesis provided is:

$H_{0}: \mu = 0\\ H_{a} : \mu > 0$

The p-value of the test obtained is 0.03

(a)

Decision rule for hypothesis testing, based on p-value, states that if the p-value is less than the significance level (α) then the null hypothesis is rejected and vice versa.

The significance level is α = 0.10

Then,

$p-value = 0.03 < \alpha = 0.10$

Thus, the null hypothesis will be rejected.

Conclusion:

The null hypothesis is rejected stating that the value of μ is more than 0.

(b)

If the decision in (a) is an error, i.e. the null hypothesis is rejected when in fact it is true, this type of error is known as type I error.

(c)

The significance level is α = 0.01

Then,

$p-value = 0.03 > \alpha = 0.01$

Thus, the null hypothesis will not be rejected.

Conclusion:

The null hypothesis was not rejected stating that the value of μ is 0.

If this decision is an error, i.e. the null hypothesis was not rejected when in fact it is false, this type of error is known as type II error.

3 0

3 years ago

Solve for f(2)<br>f(x) =-4x+3<br>f(2)=-4(2)+3<br>f(2)=?

Mila [183]

The answer would be -11

5 0

3 years ago

Solve for y 3x+11y=-5

mars1129 [50]

$\displaystyle 3x+11y=-5\quad\Big| -3x\\\\11y=-5-3x\quad\Big|:11\\\\y= -\frac{5+3x}{11}$

6 0

3 years ago

8

Nimfa-mama [501]

3
—
-2
because the answer is 6 over -4 and it simplified is that answer.

3 0

3 years ago