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cestrela7 [59]
3 years ago
7

Jason places a mirror on the ground 40 feet from the base of a tree. He walks backwards until he can see the top of the tree in

the middle of the mirror. At that point, Jason's eyes are 6 feet above the ground and he is 8 feet from the image in the mirror. What is the height of the tree?
Mathematics
2 answers:
Bas_tet [7]3 years ago
7 0
Let
x---------------> <span>the height of the tree

we know that
by using proportion
</span>\frac{40}{8} = \frac{x}{6}  \\  \\ 40*6=8*x \\  \\ x=40*6/8 \\  \\ x=30 feet
<span>
therefore

the answer is
</span><span>the height of the tree is </span>30feet
maksim [4K]3 years ago
3 0
We have to use a proportion:x is the height of a treex : 40 = 6 : 88 x = 6 * 408 x = 240x = 240 : 8x = 30 ftAnswer:The height of the tree is 30 ft.

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The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c
Anestetic [448]

Answer:

a) The mean is \mu = 60

b) The standard deviation is \sigma = 9

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when X = 55.5, Z = -0.5

So

Z = \frac{X - \mu}{\sigma}

-0.5 = \frac{55.5 - \mu}{\sigma}

-0.5\sigma = 55.5 - \mu

\mu = 55.5 + 0.5\sigma

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when X = 71.52, Z = 1.28

So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{71.52 - \mu}{\sigma}

1.28\sigma = 71.52 - \mu

\mu = 71.52 - 1.28\sigma

Since we also have that \mu = 55.5 + 0.5\sigma

55.5 + 0.5\sigma = 71.52 - 1.28\sigma

1.78\sigma = 71.52 - 55.5

\sigma = \frac{(71.52 - 55.5)}{1.78}

\sigma = 9

\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60

Question

The mean is \mu = 60

The standard deviation is \sigma = 9

6 0
2 years ago
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