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Anestetic [448]
3 years ago
6

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

Look at the picture.

Answer:

(-8, -2)

(9, 0)

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Multiply or divide as indicated. <br><br> x 2 • x 5
WARRIOR [948]
Hi there!

{x}^{2}  \times  {x}^{5}  = x {}^{2 + 5}  =  {x}^{7}

We can also write is out entirely.
{x}^{2}  = x \times x
{x}^{5}  = x \times x \times x \times x \times x
{x}^{2}  \times  {x}^{5}  = \\  (x \times x ) \times (x \times x \times x \times x \times x) =  \\ x \times x \times x \times x \times x \times x \times x =  \\  {x}^{7}
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Find the lateral surface area.
sveta [45]

Answer:

900 yd²

Step-by-step explanation:

You can draw the pattern that would need to be folded to make the figure, then find the area of that pattern (or "net"). It consists of a rectangle 10 yards wide and 60 yards long, together with another that is 20 yards long and 15 yards wide. The total area is the sum of these ...

... area = (60 yd)(10 yd) + (20 yd)(15 yd)

... = 600 yd² +300 yd²

... = 900 yd²

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3 years ago
Two numbers that multiply to -49 and add up to 0
Elenna [48]

The only way to do that is with  +7  and  -7 .

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Convert 342to base 10 and base 5
bagirrra123 [75]

The conversion answer is 23325

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14 (OM) Radicals and Estimation (2 pts) Without a calculator, estimate the radical and explain how you estimated. Then using a c
Irina-Kira [14]

Q) Without a calculator, we must estimate the value of the following expression:

3-\sqrt[]{38}.

A) I estimate 3 - √38 to be approximately -3.2.

First, we estimate the value of √38. √38 is between √36 and √49, but close to √36 (since 38 is closer to 4 than it is to 9). Since √36 is 6, √38 is probably something like 6.1 or 6.2. Filling 6.2 in the expression and simplifying, we have this:

3-6.2=-3.2.

So, I expect the number 3 - √38 to be close to -3.2.

Using a calculator we find that: 3 - √38 ≅ -3.16, which it is approximately the result that we found.

Answer

Without a calculator we find that 3 - √38 ≅ -3.2.

5 0
1 year ago
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