Given that the quadratic equation is 
We need to determine the y - value of the vertex.
<u>The x - value of the vertex:</u>
The x - value of the vertex can be determined using the formula,

where 
Substituting these values, we get;

Simplifying the terms, we get;


Thus, the x - value of the vertex is -5.
<u>The y - value of the vertex:</u>
The y - value of the vertex can be determined by substituting the x - value of the vertex ( x = -5) in the equation 
Thus, we get;

Simplifying the values, we have;


Thus, the y - value of the vertex is 49.
Answer:
Step-by-step explanation:
The minimum value of sinx is -1 when x = 3π/2, 7π/2, ...
In [2π, 4π), x = 7π/2
Answer: a = -2/3
Step-by-step explanation:
Let's start by multiplying both sides by
to simplify:




Looking only at the exponents, it seems like
, so
.
Answer:
<u>Please read below.</u>
Step-by-step explanation:
The instructions were followed, horizontal or vertical path and never diagonal:
75 76 81 66 65 14 13 8 7
74 77 80 67 64 15 12 9 6
73 78 79 68 63 16 11 10 5
72 71 70 69 62 17 2 3 4
55 56 57 58 61 18 1 22 23
54 53 52 59 60 19 20 21 24
45 46 51 50 37 36 31 30 25
44 47 48 49 38 35 32 29 26
43 42 41 40 39 34 33 28 27
Linear programming which shows the best investment strategy for the client is Max Z=0.12I +0.09B and subject to constraints are :I+ B<=25000,
0.005 I +0.004B<=250.
Given maximum investment client can make is $55000, annual return= 9%, The investment advisor requires that at most $25,000 of the client's funds should be invested in the internet fund. The internet fund, which is the more risky of the two investment alternatives, has a risk rating of 5 per thousand dollars invested. the blue chip fund has a risk rating of 4 per thousand dollars invested.
We have to make a linear programming problem.
Let
I= Internet fund investment in thousands.
B=Blue chip fund investment in thousands.
Objective function:
Max Z=0.12I+0.09B
subject to following constraints:
Investment amount: I+ B<=25000
Risk Rating: 5/100* I+4/100*B<=250 or 0.005 I +0.004B<=250
I,B>=0.
Hence the objective function is Max Z=0.12 I+ 0.09 B.
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