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3 years ago

5

Describe different ways that you can show a story problem

1 answer:

natima [27]3 years ago

3 0

Once you know your basic operations addition<span>, </span>subtraction,multiplication<span>, </span>division <span>you will encounter story problems also known as word problems that require you to read a problem and decide which operation to perform in order to get the answer. There are key words here that often indicate which operation you will use. We will give you a list of them, but remember that for many problem</span><span>s </span><span>there may not be a key word and you’ll have to use your best judgment in order to figure out what to do. </span>

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Which of the following statements are true?

Kobotan [32]

Answer:I believe the answer is D

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

F(x) = x^4- x^4 - 20<br><br> find all zeros by factoring and explaining the steps

Soloha48 [4]

No x-intercept/zero

Step by step

To find x-intercept/zero, substitute f(x)=0

F(x)=-20

0=-20

The statement is false for any value of

X=0

Since there is no solution for f(x)=0, there is no -intercept/Zero

Your welcome:)

5 0

3 years ago

Estimate the difference.<br><br> 182 - 56<br><br> A. 120<br> B. 130<br> C. 110<br> D. 150

vova2212 [387]

Answer:

Estimate by rounding

182 to 180

56 to 60

180 - 60 = 120

3 0

3 years ago

Read 2 more answers

Can someone please help me

stepladder [879]

5)

x = 132 - 42

x = 90

Answer

90 degrees, right angle

6)

180 - 126 = 54

The other two are congruent so 54/2 = 27

Answer

27

7)

An exterior angle of a triangle is equal to the sum of the opposite interior angles

So

6x = 38 + 82

6x = 120

x = 20

Answer

20

8)

Sum of interior in a triangle = 180 degrees

So

2x - 3 + 23 + 128 = 180

2x + 148 = 180

2x = 32

x = 16

Answer

16

4 0

3 years ago

Solve the problem. If s is a distance given by s(t) = + + 40 + 10. find the acceleration, alt). Q ald) = 10 ald) = 2t + 4 O alt)

QveST [7]

Answer:

C

Step-by-step explanation:

Remember that if s(t) is a position function then:

$v(t)=s'(t)$ is the velocity function and

$a(t)=s''(t)$ is the acceleration function.

So, to find the acceleration, we need to solve for the second derivative of our original function. Our original function is:

$s(t)=t^2+4t+10$

So, let's take the first derivative first with respect to t:

$\frac{d}{dt}[s(t)]=\frac{d}{dt}[t^2+4t+10]$

Expand on the right:

$s'(t)=\frac{d}{dt}[t^2]+\frac{d}{dt}[4t]+\frac{d}{dt}[10]$

Use the power rule. Remember that the derivative of a constant is 0. So, our derivative is:

$v(t)=s'(t)=2t+4$

This is also our velocity function.

To find acceleration, we want to second derivative. So, let's take the derivative of both sides again:

$\frac{d}{dt}[s'(t)]=\frac{d}{dt}[2t+4]$

Again, expand the right:

$s''(t)=\frac{d}{dt}[2t]+\frac{d}{dt}[4]$

Power rule. This yields:

$a(t)=s''(t)=2$

So, our answer is C.

And we're done!

6 0

3 years ago