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Likurg_2 [28]
3 years ago
14

What is the unit rate of 28 miles in 4 hours?

Mathematics
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

7 miles in 1 single hour

Step-by-step explanation:

28 / 4 = 7

21 / 3 = 7

14 / 2 = 7

7 / 1 = 7

Butoxors [25]3 years ago
4 0

Answer: 7 miles per hour

Step-by-step explanation:

This is a fraction equal to 28 miles divided by 4 hours.

We want a unit rate where 1 is in the denominator, so we divide top and bottom by 4.

28 miles ÷ 4

____________

4 hours ÷ 4

= 7 miles

__________

1 hour

=

7 miles

_________

hour

= 7 miles per hour

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Ludmilka [50]

Answer: The value of a is 1. The value of b is -1. The value of c is 1. The value of the discriminant is -3. The quadratic function will not intersects the  x-axis.

Explanation:

The standard form of a quadratic equation is,

p(x)=ax^2+bx+c

The given function is,

p(x)=x(x-1)+1

It can be written as,

p(x)=x^2-x+1

By comparing this equation with the standard form of quadratic equation. we get,

a=1

b=-1

c=1

The formula for discriminant is,

D=b^2-4ac

D=(-1)^2-4(1)(1)

D=1-4

D=-3

The value of the discriminant is -3.

If D<0, it means the function have no real roots.

If D=0, it means function have one real roots.

If D>0, it means function have two real roots.

Since D<0 it means the function have no real roots. So the function will not intersect the x-axis at any point.

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3 years ago
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What’s these 2 answers this for music notes
melamori03 [73]

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Step-by-step explanation:

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3 years ago
Calculus 2 master needed; stuck on evaluating the integral please show steps <img src="https://tex.z-dn.net/?f=%5Cint%20%7Bsec%2
kakasveta [241]

Answer:

\int \sec(\frac{x}{2})\tan^5({\frac{x}{2}})dx=\frac{2\sec^5(\frac{1}{2}x)}{5}-\frac{4\sec^3(\frac{1}{2}x)}{3}+2\sec(\frac{1}{2}x)+C

Step-by-step explanation:

So we have the integral:

\int \sec(\frac{x}{2})\tan^5({\frac{x}{2}})dx

First, let's use substitution to get rid of the x/2. I'm going to use the variable y. So, let y be x/2. Thus:

y=\frac{x}{2}\\dy=\frac{1}{2}dx\\2dy=dx

Therefore, the integral is:

=2\int \sec(y)\tan^5(y)dy

Now, as you had done, let's expand the tangent term. However, let's do it to the fourth. Thus:

=2\int \sec(y)\tan^4(y)\tan(y)dy

Now, we can use a variation of the trigonometric identity:

\tan^2(y)+1=\sec^2(y)

So:

\tan^2(y)=\sec^2(y)-1

Substitute this into the integral. Note that tan^4(x) is the same as (tan^2(x))^2. Thus:

=2\int \sec(y)(\tan^2(y))^2\tan(y)dy\\=2\int \sec(y)(\sec^2(y)-1)^2\tan(y)dy

Now, we can use substitution. We will use it for sec(x). Recall what the derivative of secant is. Thus:

u=\sec(y)\\du=\sec(y)\tan(y)dy

Substitute:

2\int (\sec^2(y)-1)^2(\sec(y)\tan(y))dy\\=2\int(u^2-1)^2 du

Expand the binomial:

=2\int u^4-2u^2+1du

Spilt the integral:

=2(\int u^4 du+\int-2u^2du+\int +1du)

Factor out the constant multiple:

=2(\int u^4du-2\int u^2du+\int(1)du)

Reverse Power Rule:

=2(\frac{u^{4+1}}{4+1}-2(\frac{u^{2+1}}{2+1})+(\frac{u^{0+1}}{0+1}}))

Simplify:

=2(\frac{u^5}{5}-\frac{2u^3}{3}+u)

Distribute the 2:

=\frac{2u^5}{5}-\frac{4u^3}{3}+2u

Substitute back secant for u:

=\frac{2\sec^5(y)}{5}-\frac{4\sec^3(y)}{3}+2\sec(y)

And substitute back 1/2x for y. Therefore:

=\frac{2\sec^5(\frac{1}{2}x)}{5}-\frac{4\sec^3(\frac{1}{2}x)}{3}+2\sec(\frac{1}{2}x)

And, finally, C:

=\frac{2\sec^5(\frac{1}{2}x)}{5}-\frac{4\sec^3(\frac{1}{2}x)}{3}+2\sec(\frac{1}{2}x)+C

And we're done!

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The second part gets cut off but it’s the same as the first part, we all have nothing better to do anyways so i’ll be hurt if no
andrey2020 [161]

Answer: equation: y=2x+4

initial value: 4

rate of change: 2/1

graph: the y-intercept at 4 and go up 2 and over 1 repeatedly until you’re able to draw a ray.

Table of values: (0,4) ; (1,6) ; (2,8) ; (3,10) ; (4,12)

-

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Your car has 10 gallons of gas. You use up 1 gallon for every 20 miles you travel.

Initial value: 10

Rate of change: -1/20

[[Don’t be afraid to correct me if I am wrong. It’s 1 am and I got the sudden urge to answer brain.ly questions]]

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