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joja [24]
3 years ago
11

An amount of $15,000 is invested in a fund that has a return of

Mathematics
1 answer:
IrinaVladis [17]3 years ago
6 0

Answer:

$12000 should be invested in a fund with a 4% return.

Step-by-step explanation:

Consider the provided information.

An amount of $15,000 is invested in a fund that has a return of  6%.

We need to calculate how much money is invested in a fund with a 4% return if the  total return on both investments is $1380.

Let $x should be invested in a fund with a 4% return.

The above information can be written as:

1380=15000\times 6\%+x\times 4\%

1380=15000\times \frac{6}{100}+x\times \frac{4}{100}

1380=150\times6+x\times 0.04

1380-900=0.04x\\480=0.04x\\x=12000

Hence, $12000 should be invested in a fund with a 4% return.

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The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
5x+20y=4<br> x=-4y+1<br><br> Solve for x/y
Andrews [41]

Hi there!


Looks like a lot of work is going on here.


Let's start by solving this equation for the x.


5x + 20y = 4


Step 1) Add -20y to both sides.


5x + 20y + - 20y = 4 - 20y 5x = -20y + 4


Step 2) Divide both sides by 5.


\frac{5x}{5}  = \frac{-20y + 4}{5}


x = -4y +  \frac{4}{5}


Final Answer:


x = -4y +  \frac{4}{5}


Now, let's solve for y.


Step 1) Add -5x to both sides.


5x + 20y + - 5x = 4 + - 5x 20y = -5x + 4


Step 2) Divide both sides by 20.


\frac{20y}{20} =  \frac{-5x + 4}{20}


y =  \frac{-1}{4} x +  \frac{1}{5}


Final Answer:


y =  \frac{-1}{4} x +  \frac{1}{5}


Hope this helps! :D


Hint - When you have two variables in an equation, and you want to solve for one, the other will end up in your answer. :)

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Sergio039 [100]
I’m pretty sure it is.
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