Answer:
he can rent the camera for 5 days and will have $5 left over
Step-by-step explanation: he only has $50 , and he has to pay 15 to register which will leave him with 35 left over and then he pays $6 each day and it would be 5 days of renting.
50-15+35
6x5=30 which means he pays $6 everyday for 5 days
which will leave $5 left over
Answer:
<u>tulips bulbs cost $5; and daffodil bulbs costs $8 </u>
Step-by-step explanation:
Variables can be used to create equations and set up a system of equations. I used the following variables:
Tulip bulbs= t
Daffodil bulbs= d
We need create two equations using the total sales, and amount of each item sold. Using the variables I chose I set up an equation representing the sales of each girl.
Sumalee sold 6 tulip bulbs and 6 daffodil bulbs for $78.
6t+ 6d= 78
Jennifer sold 6 tulip bulbs and 4 daffodil bulbs for $62.
6t+ 4d= 62
Using the equations we can set up a system of equations. To solve the system you can use either the substitution method or the elimination method.
(substitution)
Isolate one of the variables in the first equation.
6t+ 6d-6t = 78-6t
6d/ 6= (-6t+78)/6
d= -t+13
Substitute d= -t+13 into equation 2 replacing variable d. Using the order of operations solve for t.
6t+ 4(-t+13) = 62
6t- 4t+52 = 62
2t = 10
<u>t= 5</u>
Substituting t=5 for the value of t in equation 1, and solve of d.
6(5)+ 6d= 78
30+ 6d= 78
6d=48
<u>d=8</u>
<u>This means one package of tulips bulbs cost $5, and one bag of daffodil bulbs costs $8 </u>
First let's try to find the equation in this form : <span>y = mx + c
The gradient is given 3 . In a line's equation, x's coefficient represents the line's gradient.
So equation of a line with the gradient of 3, would look like this ;
</span>

<span>
Now a point that the line passes through is given, (1, 2)
This point's x-coordinate is 1 and y-coordinate is 2.
So we'll plug its x-coordinate value in the equation and also y-coordinate value. So we can solve it.
As you know, </span>

and



We found c = -1
Also in a line's equation, c is constant and it represents the line's y-intercept
So let's build the line's equation.

and



We found the line's equation in this form,

Now let's turn it into this form,


Final answers,

and

I hope this was clear enough :)
<span>
</span>
1. y=4x
2. y=-7x-8
3. y=5x+63
4. y=¾x+8
5. y=-3x-½
6. y=1x-3
7. y=2
8. y=-2x+1
9. y=4x+7
wor<u>k for 9</u>
1=4(2)+b
1= 8 +b
-8 -8
7=b
10. y=0
11. y=¾x+6
<u>work </u><u>for </u><u>1</u><u>1</u>
<em>9</em><em> </em><em>=¾(4)+b</em>
<em>=¾(4)+b9</em><em> </em><em>= 3</em><em> </em><em> </em><em> </em><em>+b</em>
<em>+b-3=-3</em>
<em>+b-3=-3 6=</em><em>b</em>
<em>1</em><em>2</em><em>.</em><em> </em><em>sorry </em><em>I </em><em>haven't</em><em> </em><em>done </em><em>thai </em><em>one </em><em>in </em><em>a </em><em>while.</em>
<em>I </em><em>was </em><em>too </em><em>lazy </em><em>to </em><em>include</em><em> </em><em>the </em><em>work </em><em>for </em><em>the </em><em>first </em><em>couple</em><em> </em><em>of </em><em>answers</em><em> </em><em>although</em><em> </em><em>I </em><em>recommend</em><em>.</em><em> </em>
<em>M</em>
<em>A</em>
<em>T</em>
<em>H</em>
<em>W</em>
<em>A</em>
<em>Y</em>
<em>they </em><em>include</em><em> </em><em>work </em><em>with </em><em>ads</em>