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vovangra [49]
3 years ago
10

What is x in the equation -3(7-2x)+3=8x-10

Mathematics
2 answers:
damaskus [11]3 years ago
4 0

Answer:

x=-4

Step-by-step explanation:

−3(7−2x)+3=8x−10

Step 1: Simplify both sides of the equation.

−3(7−2x)+3=8x−10

(−3)(7)+(−3)(−2x)+3=8x+−10(Distribute)

−21+6x+3=8x+−10

(6x)+(−21+3)=8x−10(Combine Like Terms)

6x+−18=8x−10

6x−18=8x−10

Step 2: Subtract 8x from both sides.

6x−18−8x=8x−10−8x

−2x−18=−10

Step 3: Add 18 to both sides.

−2x−18+18=−10+18

−2x=8

Step 4: Divide both sides by -2.

−2x

−2

=

8

−2

x=−4

3241004551 [841]3 years ago
3 0

Answer:

-4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3(7−2x)+3=8x−10

(−3)(7)+(−3)(−2x)+3=8x+−10(Distribute)

−21+6x+3=8x+−10

(6x)+(−21+3)=8x−10(Combine Like Terms)

6x+−18=8x−10

6x−18=8x−10

Step 2: Subtract 8x from both sides.

6x−18−8x=8x−10−8x

−2x−18=−10

Step 3: Add 18 to both sides.

−2x−18+18=−10+18

−2x=8

Step 4: Divide both sides by -2.

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snow_tiger [21]

Answer:

he can rent the camera for 5 days and will have $5 left over

Step-by-step explanation: he only has $50 , and he has to pay 15 to register which will leave him with 35 left over and then he pays $6 each day and it would be 5 days of renting.

50-15+35

6x5=30 which means he pays $6 everyday for 5 days

which will leave $5 left over

8 0
2 years ago
Sumalee and Jennifer are selling flower bulbs for a school fundraiser. Customers can package of tulip bulbs and bags of daffodil
Alecsey [184]

Answer:

<u>tulips bulbs cost $5; and daffodil bulbs costs $8 </u>

Step-by-step explanation:

Variables can be used to create equations and set up a system of equations. I used the following variables:

Tulip bulbs=  t

Daffodil bulbs= d

We need create two equations using the total sales, and amount of each item sold. Using the variables I chose I set up an equation representing the sales of each girl.

Sumalee sold 6 tulip bulbs and 6 daffodil bulbs for $78.

6t+ 6d= 78

Jennifer sold 6 tulip bulbs and 4 daffodil bulbs for $62.

6t+ 4d= 62

Using the equations we can set up a system of equations. To solve the system you can use either the substitution method or the elimination method.

(substitution)

Isolate one of the variables in the first equation.

6t+ 6d-6t  = 78-6t  

6d/ 6= (-6t+78)/6

d= -t+13

Substitute d= -t+13 into equation 2 replacing variable d. Using the order of operations solve for t.

6t+ 4(-t+13) = 62

6t- 4t+52 = 62

2t = 10

<u>t= 5</u>

Substituting t=5 for the value of t in equation 1, and solve of d.

6(5)+ 6d= 78

30+ 6d= 78

6d=48

<u>d=8</u>

<u>This means one package of tulips bulbs cost $5, and one bag of daffodil bulbs costs $8 </u>

4 0
3 years ago
Twenty-eight people in student council are running for the offices of president and vice-president. In how many different ways c
motikmotik
I think the answer is 55
5 0
3 years ago
Find the equation of a straight line passing throught the point listed and having the given gradient. Express your answer in the
Igoryamba
First let's try to find the equation in this form : <span>y = mx + c 

The gradient is given 3 . In a line's equation, x's coefficient represents the line's gradient.

So equation of a line with the gradient of 3, would look like this ;

</span>y= 3x + c
<span>
Now a point that the line passes through is given, (1, 2) 

This point's x-coordinate is 1 and y-coordinate is 2.

So we'll plug its x-coordinate value in the equation and also y-coordinate value. So we can solve it.

As you know, </span>x=1 and y=2

y = 3x + c

2\quad =\quad 3\cdot 1+c\\ \\ 2\quad =\quad 3+c\\ \\ 2-3\quad =\quad c\\ \\ -1\quad =\quad c

We found c = -1 

Also in a line's equation, c is constant and it represents the line's y-intercept

So let's build the line's equation.

m=3 and c=-1

y= mx + c

y= 3x -1

We found the line's equation in this form, y= mx + c

Now let's turn it into this form, ax + by + c = 0

y\quad =\quad 3x-1\\ \\ y-3x\quad =\quad -1\\ \\ y-3x+1\quad =\quad 0\\ \\ -3x+y+1\quad =\quad 0

Final answers,

\boxed { y\quad =\quad 3x-1 }

and 

\boxed { -3x+y+1\quad =\quad 0 }

I hope this was clear enough :)




<span>


</span>
5 0
3 years ago
Read 2 more answers
PLS HELPPPPP DUE TODAYYYY
Dafna1 [17]

1. y=4x

2. y=-7x-8

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9. y=4x+7

wor<u>k for 9</u>

1=4(2)+b

1= 8 +b

-8 -8

7=b

10. y=0

11. y=¾x+6

<u>work </u><u>for </u><u>1</u><u>1</u>

<em>9</em><em> </em><em>=¾(4)+b</em>

<em>=¾(4)+b9</em><em> </em><em>= 3</em><em> </em><em> </em><em> </em><em>+b</em>

<em>+b-3=-3</em>

<em>+b-3=-3 6=</em><em>b</em>

<em>1</em><em>2</em><em>.</em><em> </em><em>sorry </em><em>I </em><em>haven't</em><em> </em><em>done </em><em>thai </em><em>one </em><em>in </em><em>a </em><em>while.</em>

<em>I </em><em>was </em><em>too </em><em>lazy </em><em>to </em><em>include</em><em> </em><em>the </em><em>work </em><em>for </em><em>the </em><em>first </em><em>couple</em><em> </em><em>of </em><em>answers</em><em> </em><em>although</em><em> </em><em>I </em><em>recommend</em><em>.</em><em> </em>

<em>M</em>

<em>A</em>

<em>T</em>

<em>H</em>

<em>W</em>

<em>A</em>

<em>Y</em>

<em>they </em><em>include</em><em> </em><em>work </em><em>with </em><em>ads</em>

6 0
3 years ago
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