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Gelneren [198K]
3 years ago
12

Figure PQRS is a rectangle.

Mathematics
1 answer:
il63 [147K]3 years ago
6 0

Answer:

4th option.

Step-by-step explanation:

PQ is not congruent to QR, instead it is PQ is perpendicular to QR.

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What is x^2 -11x+19=-5 as standard form?
IrinaVladis [17]

Answer:

<em>Standard Form; x^2 - 11x + 24 = 0</em>

Step-by-step explanation:

Simplify rewrite such that the quadratic equation has 0 isolated on the right or left side, most commonly right side;

x^2 - 11x + 19 = - 5 ⇒ Add 5 on either side of equation,

<em>Standard Form; x^2 - 11x + 24 = 0</em>

4 0
3 years ago
30 POINTS,NEED HELP ASAP !!!
zaharov [31]

Answer: OPTION A.

Step-by-step explanation:

You can observe that in the figure CDEF the vertices are:

C(-2,-1),\ D(-2,0),\ E(2,2)\ and\ F(2,1)

And in the figure C'D'E'F'  the vertices are:

C'(-8,-4),\ D'(-8,0),\ E'(8,8)\ and\ F'(8,4)

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:

For C'(-8,-4) and C(-2,-1):

\frac{-8}{-2}=4\\\\\frac{-4}{-1}=4

Let's choose another vertex. For E'(8,8) and E(2,2):

\frac{8}{2}=4\\\\\frac{8}{2}=4

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.

Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:

(x, y)→(4x, 4y)

7 0
3 years ago
Read 2 more answers
Two cylinders are similar. The volume of the larger cylinder is 343 ft³ and the volume of the smaller cylinder is 125 ​​ft³. The
andreev551 [17]
Both cylinder are similar
Volume of a cylinder is πr^2h
if we consider both has same radius as they are similar
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125/343=5/h
0.36=5/h
h=5/0.36
h=13.72 ft

6 0
3 years ago
For a quantity that changes frequently from month to month, the best kind of graph is a pie chart.
lana66690 [7]
For a quantity that changes frequently from month to month, the best kind of graph is a pie chart.a true
3 0
3 years ago
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Write an equation for a line that is parallel to 2x+5y=15 and passes through the point (-10, 3)​
Lyrx [107]

Answer:

The equation of the line is,

y =  -  \frac{2}{5} x - 1

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

2x + 5y = 15

5y = 15 - 2x

y = 3 -  \frac{2}{5} x

y =   - \frac{2}{3} x + 5

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

y =   - \frac{ 2}{5}x + b

let \: x =  - 10,y = 3

3 =  -  \frac{2}{5} ( - 10) + b

3 = 4 + b

3 - 4 = b

b =  - 1

3 0
3 years ago
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