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Anon25 [30]
3 years ago
14

Nilsa is working on a 60 minute math test. There are 20 questions on the test. If it takes her 20 minutes to complete 12 of the

questions, what is the
greatest amount of time on average she can spend on each of the 8 remaining questions? Please write an inequality too :)
Mathematics
1 answer:
nadezda [96]3 years ago
8 0
She can't spend more than 5 minutes on each of the remaining 8 questions.

It's a 60-minute test in which she has spent 20 minutes answering 12 questions. That means that there are 40 minutes remaining (60-20) to answer the remaining 8 questions. That's 40 divided by 8 = 5.
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Use the function below to find f(-2).<br> Help pls..
xenn [34]

Answer:

1/25

Step-by-step explanation:

f(x) = 5^x

f(-2) = 5^-2

       We know that a^-b = 1/a^b

      = 1/5^2

    = 1/25

4 0
3 years ago
Pls help no links
irina [24]

Answer:

lets say "w" is weeks

400 - 20w

Step-by-step explanation:

u have 400, and u take out 20 per week

3 0
3 years ago
Help please!What is the x-intercept of the line?X=33 Y=-22X=52 Y=-33X=71 Y=-44
tekilochka [14]

x intercept is -5

Explanation

Step 1

find the slope of the line:

when you know 2 points of the line, you can find the slope, by using:

\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}

then,Let

P1(33,-22)

P2(52,-33)

replace,

\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-33-(-22)}{52-33}=\frac{-33+22}{19}=\frac{-11}{19} \\ \text{slope}=-\frac{11}{19} \end{gathered}

Step 2

find the equation of the line

y-y_1=slope(x-x_1)\rightarrow equation

let

\begin{gathered} \text{slope}=-\frac{11}{19} \\ P1(33,-22) \end{gathered}

replace,

\begin{gathered} y-y_1=slope(x-x_1)\rightarrow equation \\ y-(-22)=-\frac{11}{19}(x-33) \\ y+22=-\frac{11}{19}x+\frac{363}{19} \\ to\text{ isolate y, subtract 22 in both sides} \\ y+22-22=-\frac{11}{19}x+\frac{363}{19}-22 \\ y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \end{gathered}

now, we have the equation of the line, to get the x intercetp ( it is when y=0)

replace

\begin{gathered} y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \\ 0=-\frac{11}{19}x-\frac{55}{19} \\ \text{isolate x} \\ \frac{11}{19}x=-\frac{55}{19} \\ 11x=-\frac{55\cdot19}{19} \\ 11x=-55 \\ \text{divide both sides by 11} \\ \frac{11x}{11}=\frac{-55}{11} \\ x=-5 \end{gathered}

so, the x intercetp is -5.

I hope this helps you

6 0
1 year ago
I spent 25 Points, PLEASE HELP! In a graph, x represents the number of months since a business opened, and y represents the tota
vlada-n [284]
First find the slope.  m=(y2-y1)/(x2-x1)

m=(4225-1990)/(5-2)=745,

m is the slope, this represents the amount of money earned each month that the business operates.

so far we have:

y=745x+b, using any point we can solve for b, I'll use (2,1990)

1990=745(2)+b

1990=1490+b

500=b

b is the y-intercept which is $500, it represents the amount of moeny that the business started with.


3 0
3 years ago
Read 2 more answers
What is 40/3 as a mixed number
Tanzania [10]
\frac{40}{3} = \frac{39+1}{3}=\frac{39}{3}+\frac{1}{3} = 13\frac{1}{3}
3 0
3 years ago
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