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julsineya [31]
4 years ago
12

Can someone help me answer a question anybody I need help ASP

Mathematics
1 answer:
Tom [10]4 years ago
4 0

Step-by-step explanation:

yes i ccsan help but i dont know what your question is

the answer is 2.66 (continuous sixes)

is this what the question is?

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Can you please help me out with this question, Thank youu❤️
scoundrel [369]

Answer:

D

Step-by-step explanation:

D is not a correct way to label the following angle because the letter on the angle starts with w, then x, then y and not y, then x, then w...

5 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?
lesya [120]

Answer:

F27

Step-by-step explanation:

5 0
3 years ago
"Scenario: You have to pay your share of the rent today. The total rent for your apartment is $1762.50. You have two roommates t
topjm [15]

Answer:

You would be required to pay $587.50

Step-by-step explanation:

Divide $1762.50 by three:

You get $587.50

To find how much you have left:

Subtract 587.50 from 668.72:

You'd be left with

$81.22

3 0
3 years ago
Read 2 more answers
Question 5 (1 point)
dexar [7]

Answer:

4.5

Step-by-step explanation:

8 + 7 + 6 + 5 + 4 + 3 + 2 + 1/8

36/8

=4.5

3 0
3 years ago
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