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2 years ago

Help ill give 5 stars if you get it correct

Mathematics

2 answers:

yulyashka [42]2 years ago

5 0

Answer:

[B] $2\frac{8}{9}$

Step-by-step explanation:

First of all, it not asking for the answer it asking for the first step.

Secondly, both number are positive (Before subtract)

Hence, this leads us to 2 more answer choices.

When model a number or a fraction on the number line you put the first Value on the number line then the second Value.

Therefore, we can conclude that [B] 2 8/9 is the correct answer.

[RevyBreeze]

Jlenok [28]2 years ago

3 0

Answer:

B is the answer

Step-by-step explanation: Ok so the problem we are working with is

8 2/9-4 2/3. We will eliminate all the negative answers. So we only have 2 options. When we actually think logically B is the only possible answer.

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Write the equation of the line in fully simplified slope-intercept form.

tiny-mole [99]

Step-by-step explanation:

x= -7 y=0

x= -3 y =-6

y =mx+b

b=-7

-6= -3m -7

-3m = 1

m= -1/3

y= -x/3 -7

$y = - \frac{x}{3} - 7$

8 0

3 years ago

Please help now with homework

damaskus [11]

The correct answer is 1.25 dollars per pound. You can check it by multiplying it with 4.16

5 0

3 years ago

4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2

Anna007 [38]

Answer:

Given data:

4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2

Put the data in the ascending order:

1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6, 8

Mean, the average:

(1 + 2*5 + 3*4 + 4*4 + 5*2 + 6 + 8)/18 = 3.5

Median, average of middle two numbers:

Mode, the most repeated number:

2 (repeated 5 times)

Mean is normally the best measure of central tendency, same applies to this data.

6 0

3 years ago

Read 2 more answers

Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3

Whitepunk [10]

If $f(x)=4x-3$ :

$\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4$

If $f(x)=4x^{-3}$ :

$\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}$