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3 years ago

6

I’m stuck on this which one is correct ?

2 answers:

german3 years ago

8 0

You know that the angles in a triangle always add up to 180 degrees, and you know angle a is 35 degrees and angle C is 90 degrees (as indicated by the little square). You must add 90 + 35 which would be 125 degrees,and then subtract 180-125. Basically, for this to be a triangle this last unknown angle must add up with the other two to give you 180, the only possible answer is 55; which would be C

stepan [7]3 years ago

3 0

The answer is c. Bcs A + B = 90 [ 35 + 55 = 90]

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PLEASE ANSWER CORRECTLY! WILL GIVE BRAINLIEST!

vaieri [72.5K]

Answer:

0.7938

Step-by-step explanation:

z1 = (125-100)/15 = 1.667

P( < 125) = 0.9522

z2 = (85-100)/15 = -1

P( > 85) = 0.8413

0.9522 + 0.8413 - 1 = 0.7935

4 0

3 years ago

For the parallelogram find the value of x,y,and z

Nat2105 [25]

Answer:

X = 119, Y = 61, Z = 119

Step-by-step explanation:

These are supplementary angles and equal 180.

180 - 61 = 119

Opposite angles are congruent

5 0

3 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

Evaluate the expression 2x +y for x=7and y=6

Andre45 [30]

Answer: 20

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

F - 3/4=5/6. Please answer soon thanks

ad-work [718]

F - 3/4 = 5/6
Add 3/4 to both sides to get
F = 5/6 + 3/4 = 19/12

5 0

3 years ago