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Gennadij [26K]
3 years ago
6

I’m stuck on this which one is correct ?

Mathematics
2 answers:
german3 years ago
8 0
You know that the angles in a triangle always add up to 180 degrees, and you know angle a is 35 degrees and angle C is 90 degrees (as indicated by the little square). You must add 90 + 35 which would be 125 degrees,and then subtract 180-125. Basically, for this to be a triangle this last unknown angle must add up with the other two to give you 180, the only possible answer is 55; which would be C
stepan [7]3 years ago
3 0
The answer is c. Bcs A + B = 90 [ 35 + 55 = 90]
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Tina says that 3.4 x 105 is greater than 8.25 x 104. Is she correct? Justify your answer.
Anna71 [15]

Answer:

No, Tina is not correct since 3.4 × 105 = 357 and 8.25 × 104 = 858

6 0
2 years ago
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Find the HCF of 960 and 432​
sdas [7]

Answer:

48

Step-by-step explanation:

Using Uclid's division algorithm, the HCF of 960 and 432 can be obtained as follows:

Here, 960 is greater and 432 is smaller. We divide 960 by 432.

STEP 1:

960 = 432*2 + 96

STEP 2:

Divide divisor (432) by remainder (96)

432 = 96 * 4 + 48

STEP 3:

Divide divisor (96) by remainder (48)

96 = 48 * 2 + 0

Since, remainder at this step is zero (0), so the HCF would be the divisor of this step which is 48.

Thus, HCF of 960 and 432 is 48

4 0
2 years ago
What value of x will solve the equation 3/4x + 10 = 4
deff fn [24]

Answer:

-8

Step-by-step explanation:

3 0
2 years ago
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A impossible<br> B unlikely<br> equally likely<br> D likely<br> E<br> certain
maks197457 [2]
C equally likely since there is a 50/50 chance of each outcome
7 0
3 years ago
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1. The zeros of a quadratic relation are 3 and The second differences are positive
nata0808 [166]

Answer:

The optimal, vertex, value will be a minimum

Step-by-step explanation:

The given zeros of the quadratic relation are 3 and 3

The sign of the second differences of the quadratic relation = Positive

Whereby the two zeros are the same as x = 3, we have that the point 3 is the optimal value or vertex (the repeated point in the graph of the quadratic relation) of the quadratic relation

Whereby, the table of values for the quadratic relation from which the second difference is found starts from x = 3, we have;

To the right of the coordinate points of the zeros of the quadratic relation, the positive second difference in y-values gives as x increases, y increases which gives a positive slope

By the nature of the quadratic graph, the slope of the line to the left of the coordinate point of the zeros of the quadratic relation will be of opposite sign (or negative). The quadratic relation is cup shaped and the zeros, therefore, the optimal value will be a minimum of the quadratic relation

8 0
2 years ago
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