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kogti [31]
3 years ago
12

Consider the sequence 256,128,64,32 find the 12th term of the sequence

Mathematics
1 answer:
Akimi4 [234]3 years ago
8 0

Answer:

It would be 0.125

Step-by-step explanation:

I hope this helps you.

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Find the area bounded by the graphs of the indicated equations over the given interval.
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Answer:

48

Step-by-step explanation:

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First, find the integral of x^2-25.

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integral of a constant is that constant times x.

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y =  {x}^{2}  - 25

We then get

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Then we evaluate at 0

\frac{0 {}^{3} }{3}  - 25(0) = 0

Next, we subtract the the answer then we get

48 - 0 = 48

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