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3 years ago

Consider the sequence 256,128,64,32 find the 12th term of the sequence

Mathematics

1 answer:

Akimi4 [234]3 years ago

8 0

Answer:

It would be 0.125

Step-by-step explanation:

I hope this helps you.

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Please help me ASAP, thank you ^-^. The radius of the cone is 7 in and y = 25 in. What is the volume of the cone in terms of π?

MrRa [10]

<h2>Answer:</h2>

The volume of the cone in terms of π is:

A. 392π in³

<h2>Step-by-step explanation:</h2>

The radius of the cone i.e. r is: 7 in.

and the slant height of the cone i.e. l=y=25 in.

and let h=x be the height of the cone.

Now, using the Pythagorean Theorem we have:

$l^2=r^2+h^2\\\\i.e.\\\\h^2=l^2-r^2\\\\i.e.\\\\h^2=(25)^2-7^2\\\\i.e.\\\\h^2=625-49\\\\i.e.\\\\h^2=576\\\\i.e.\\\\h=\sqrt{576}\\\\i.e.\\\\h=24$

Hence, we get:

$h=x=25\ in.$

Now, the volume of the cone is given by:

$Volume=\dfrac{1}{3}\pi r^2h\\\\i.e.\\\\Volume=\dfrac{1}{3}\times\pi\times (7)^2\times 24\\\\i.e.\\\\Volume=392\pi\ in^3$

Hence, the answer is: Option: A

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3 years ago

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This floor has a grape juice stain. Tyler wants to cover the stain with the green carpet. Perform a series of two or more transf

nataly862011 [7]

Rotation and dilation

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3 years ago

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The first four terms of a sequence are shown below:

Tems11 [23]

A f(1) = 9, f(n + 1) = f(n) − 4; for n ≥ 1

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3 years ago

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Object A has a mass of 12 g and a density of 3 g/cm Object B has a mass of 12 g and a density of 5 g/cm and Which object has a g

sasho [114]

Answer:

Object A has greater volume and it is 1.6 cubic cm greater than Object B

Step-by-step explanation:

Given data is:

Object A:

Mass = m1 = 12g

Density = d1 = 3g/cm^3

Object B:

Mass = m2 = 12g

Density = d2 = 5g/cm^3

The relationship between mass, volume and density is given by the following formula

$density = \frac{mass}{volume}$

Let v1 be the volume of object A and v2 be the volume of object B

Now,

Using the given relationship

$d_1 = \frac{m_1}{v_1}\\v_1 = \frac{m_1}{d_1}\\v_1 = \frac{12}{3}\\v_1 = 4\ cm^3\\And\\v_2 = \frac{m_2}{d_2}\\v_2 = \frac{12}{5}\\v_2 = 2.4\ cm^3$

Difference between volumes is: 4-2.4 = 1.6

It can clearly be seen that the volume of object A is greater than object B.

Hence,

Object A has greater volume and it is 1.6 cubic cm greater than Object B

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2 years ago

25 POINTS! RIGHT ANSWERS ONLY! Explanation is optional.

mojhsa [17]

2 then 450 are your answers

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